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jpv
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jpv
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I dont have any OA. But I agree with (B).
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MA
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A. It must be an even number=> must is too strong.
B. It may be an even number but doesn't have to be=> may be ok.
C. It cannot be an even number=> cannot be too strong.
D. It cannot be a multiple of 6=> cannot be too strong.
E. It can be a multiple of 6 or an even number, but not both=> can be ok, but cannot be both means cannot be a multiple of 6 and even integer. too strong too because all multiples of 6 are even integers.


B wins.
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ywilfred
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1)If num is multiple of 6, then num is multiple of 3
If 1) is true, then num is even

A. It must be an even number.
- Out. We're not sure of that.

B. It may be an even number but doesn't have to be.
- This is the answer. There's a possibility it might be even, but it doesn't have to be the case

C. It cannot be an even number.
- Out.

D. It cannot be a multiple of 6.
- Can't tell

E. It can be a multiple of 6 or an even number, but not both.
- Out.

B it is.



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