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Hi, lets see what all we have.. 1) year 1999.. number of students=5500 number of faculty=5500/R..
2) year 2004..... number of students=5500(100-S)/100..where S is the % change over 5 academic years number of faculty=5500/R*(100+F)/100..where F is the % change over 5 academic years.. so number of students/number of faculty members= [5500(100-S)/100]/[5500/R*(100+F)/100] =(100-S)/(100+F) * R ans D
number of students=5500(100-S)/100..where S is the % change over 5 academic years number of faculty=5500/R*(100+F)/100..where F is the % change over 5 academic years..
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Hi chetan2u, Can you please tell me how you got the below step ? 100-S and 100+F ..
chetan2u
number of students=5500(100-S)/100..where S is the % change over 5 academic years number of faculty=5500/R*(100+F)/100..where F is the % change over 5 academic years..
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i din understand from where 100 came all of a sudden.. is there anything i am missing ?
just a query, is the answer (100-S)/(100+F) * R ? cause the one mentioned in screenshot is different.
number of students=5500(100-S)/100..where S is the % change over 5 academic years number of faculty=5500/R*(100+F)/100..where F is the % change over 5 academic years..
Hi chetan2u, Can you please tell me how you got the below step ? 100-S and 100+F ..
chetan2u
number of students=5500(100-S)/100..where S is the % change over 5 academic years number of faculty=5500/R*(100+F)/100..where F is the % change over 5 academic years..
i din understand from where 100 came all of a sudden.. is there anything i am missing ?
just a query, is the answer (100-S)/(100+F) * R ? cause the one mentioned in screenshot is different.
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Hi, There is a decrease in the number of students, say s%... Then the student who were initially 5500 goes down to 5500*(100-s)/100.. Example.. the decrease was 20%, so number is 5500*(100-20)/100=5500*80/100.. Similarly for increase in faculty (100+F)/100..
Hi, There is a decrease in the number of students, say s%... Then the student who were initially 5500 goes down to 5500*(100-s)/100.. Example.. the decrease was 20%, so number is 5500*(100-20)/100=5500*80/100.. Similarly for increase in faculty (100+F)/100..
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Thank you so much chetan2u for your explanation Kudos to you .. But the answer given is (100+S)/(100+F) * R
Since Students decrease, it should be 100-s right ?
Since Students decrease, it should be 100-s right ?
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I think the process used is completely right, but there is a minor flaw. S represents the change and not the decrease itself. The change has to be used as +S, and when the change is on the negative side (there is a decrease), S will assume a -ve value.
Example: If there is an increase, S = +5%, or in case of decrease, S = -7% Over here in the working provided, in case of increase, S = -5% and in case of decrease, S = 7%. The general way of depiction is wrong.
But they have provided S is decreasing right ? Since the value is not given .. we are giving a general expression ?
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The question defines S to be a percentage change in the number of students. We need a formula which will generalize both the increase and the decrease. Hence the positive sign. Small example: Let's say the question had 2 parts - One with a x% increase and the other with a x% decrease. The easiest way to answer this is to write a formula which will satisfy both the equation instead of writing 2 formulae one with +S and the other with -S. Rather you would probably write a formula with +S and replace +S = x% for increase and +S = -x% for decrease. A mathematical corollary would be formula for compound interest. We do not change the +ve sign in the bracket to -ve for decreasing Rs in A=P[1+(R/100)]^n, rather replace R with a -ve value.
Remember, formulae should be general and conventional.
Hope this explains and helps you
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