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01 Jun 2021, 21:00
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d: 0.79
A: 0.62
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
56% (02:46) correct
44%
(02:30)
wrong
based on 423
sessions
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An employee of a certain company is creating the smallest possible cubic box into which a spherical piece of art will be placed for an exhibit. The longest distance around the piece of art is \(\frac{π^2}{4}\) meters.
Select the approximate value, in meters, of the sphere's diameter d and select the desired value, in meters squared, of the area A of the box's interior base. Make only two selections, one in each column.
Select the approximate value, in meters, of the sphere's diameter d and select the desired value, in meters squared, of the area A of the box's interior base. Make only two selections, one in each column.
| d | A | |
| 0.56 | ||
| 0.62 | ||
| 0.68 | ||
| 0.75 | ||
| 0.79 | ||
| 0.83 |
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Official Answer
d: 0.79
A: 0.62
BEINGRATUL
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Joined: 24 Nov 2020
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02 Jun 2021, 10:04
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Longest Area Around the spherical piece of art is its circumpherence i.e. 2*pi*r
so 2*pi*r= (pi)^2/4
r comes as pi/8 hence Diameter D= pi/4=0.79
Area of Base A is D^2= 0.79^2=0.62
so 2*pi*r= (pi)^2/4
r comes as pi/8 hence Diameter D= pi/4=0.79
Area of Base A is D^2= 0.79^2=0.62
Ariel4Ighuma
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19 Mar 2023, 09:00
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Sajjad1994
On this kind of question, one has to be careful not to over approximate. For example, using 3 as an approximate value for pi changes the answers.
