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Vidds0214
Does this partially come under geometry?
­
Yes. However, ­while specific geometry knowledge is not tested on GMAT Focus, not everything involving shapes, volumes, or areas requires specialized geometry knowledge. The area of a square or rectangle, the volume of a cube or rectangular solid, and the Pythagorean theorem are not considered specific geometry knowledge by the GMAT and can still be tested. Moreover, a question can involve shapes but test another area, such as combinations or other topics. There are several questions involving these concepts in the GMAT Prep Focus mocks
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case 2 2 (lb+bh+hl) = should it not be 2(2.3+2.2+2.3_) = 2(6+4+6) = 32 ? how is it 22


catinabox
Let's assume that the side of the cube is of length = x

­In the base case,
Surface area of a cube = 6x^2
Surface area of 6 cubes = 6* 6x^2 = 36x^2

Case 1:
1x6 Matrix
This is a cuboid of length = 6x, breadth =x, and height = x.
Surface area = 2 * x^2 + 4 * (6x*x) = 2x^2 + 24x^2
= 26x^2

Savings in area over base case = (36x^2 - 26x^2 )/36x^2 = 10/36 = 28%

Case 2:
2x3 Matrix
This is a cuboid of length =3x, breadth = 2x and height = 2x
Surface area = 2 * ( 2x*3x + x*2x + x*3x)
= 22x^2

Savings in area over base case = (36x^2 - 22x^2)/36^2 = 14/36 = 39%
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catinabox
Let's assume that the side of the cube is of length = x

­In the base case,
Surface area of a cube = 6x^2
Surface area of 6 cubes = 6* 6x^2 = 36x^2

Case 1:
1x6 Matrix
This is a cuboid of length = 6x, breadth =x, and height = x.
Surface area = 2 * x^2 + 4 * (6x*x) = 2x^2 + 24x^2
= 26x^2

Savings in area over base case = (36x^2 - 26x^2 )/36x^2 = 10/36 = 28%

Case 2:
2x3 Matrix
This is a cuboid of length =3x, breadth = 2x and height = 2x
Surface area = 2 * ( 2x*3x + x*2x + x*3x)
= 22x^2

Savings in area over base case = (36x^2 - 22x^2)/36^2 = 14/36 = 39%
Hi catinabox

In case 2 the breadth is misrepresented as 2x (against x)

However the calculation considers x

-it's Satvik-
I was here, I was solving & I was learning
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Is this question relevant for the focus edition? Are we supposed to memorise the formulae?
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Robo_123
Is this question relevant for the focus edition? Are we supposed to memorise the formulae?
I believe your doubt is addressed here: https://gmatclub.com/forum/six-identica ... l#p3450034 Let me know if any questions.
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The dimensions of 2x3 cube matrix should be 3x, 2x and x. Please check.

TIA
catinabox
Let's assume that the side of the cube is of length = x

­In the base case,
Surface area of a cube = 6x^2
Surface area of 6 cubes = 6* 6x^2 = 36x^2

Case 1:
1x6 Matrix
This is a cuboid of length = 6x, breadth =x, and height = x.
Surface area = 2 * x^2 + 4 * (6x*x) = 2x^2 + 24x^2
= 26x^2

Savings in area over base case = (36x^2 - 26x^2 )/36x^2 = 10/36 = 28%

Case 2:
2x3 Matrix
This is a cuboid of length =3x, breadth = 2x and height = 2x
Surface area = 2 * ( 2x*3x + x*2x + x*3x)
= 22x^2

Savings in area over base case = (36x^2 - 22x^2)/36^2 = 14/36 = 39%
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IMO no need of any formula,
take each side of cube as 1 unit, total area of each is 6 therefore 6 cubes will be 36 unit^2
Now when u combine it to a cuboid, notice the number of sides thats not used,
1st cube ->1
2nd cube -> 2
the middle cubes all receive 2 in this case and the last cube is again 1, totally 10 sides not used as compared to before so 10/36*100=28%

For second case,
the middle ones have 3 sides unused this time and the corner ones have each 2 unused
therefore total=2+3+2+2+3+2=14

Percent=14/36*100=39%


kdipayan
The dimensions of 2x3 cube matrix should be 3x, 2x and x. Please check.

TIA

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