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Bismuth83
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For all real values of [m]x[/m], the function [m]f(x)[/m] has the form 06 May 2025, 21:57
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v: 0 w: \(\frac{-1}{4}\)
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85% (01:13) correct 15% (01:47) wrong based on 223 sessions

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For all real values of \(x\), the function \(f(x)\) has the form: \(f(x)=(x^2−4)^{−1}\). Select one value for \(v\) and one value for \(w\) that fulfills the condition that \(f(v) = w.\)
v w
\(\frac{-1}{4}\)
0
\(\frac{1}{4}\)
\(\frac{1}{3}\)
3
4
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v: 0 w: \(\frac{-1}{4}\)
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For all real values of [m]x[/m], the function [m]f(x)[/m] has the form 07 May 2025, 01:45
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This question is a repeated question and has already been discussed here: https://gmatclub.com/forum/for-all-real ... l#p3547950


First, solve this expression \(f(x)=(x^2−4)^{−1}\)

We will get value for x as 0, and if put the value for x as 0 into equation \((x^2−4)^{−1}\) we will get the value as = -\(\frac{1}{4}\)

So, the value for \(v\) is 0 and value for \(w\) is -\(\frac{1}{4}\)
Bismuth83
For all real values of \(x\), the function \(f(x)\) has the form: \(f(x)=(x^2−4)^{−1}\). Select one value for \(v\) and one value for \(w\) that fulfills the condition that \(f(v) = w.\)
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