1. We are asked to
fill in the blanks, however to do so, we must first
find the year with the greatest total number of hail events.
2. Let's calculate the total number of hail events for all 5 years:
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Year 1. Small + Medium + Large \(= 6 + 3 + 2 = 11\).
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Year 2. Small + Medium + Large \(= 6 + 5 + 2 = 13\).
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Year 3. Small + Medium + Large \(= 5 + 3 + 3 = 11\).
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Year 4. Small + Medium + Large \(= 10 + 4 + 1 = 15\).
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Year 5. Small + Medium + Large \(= 7 + 2 + 3 = 12\).
Here, year 4 clearly has the largest amount.
3. During year 4 the greatest amount of hail events were small (10) and the least were large (1).
4. Our answer will be:
D1 - small and D2 - large.
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In practice, you can notice how the spike for year 4 (small hail events) is so large and the other two hail events are comparable, so years 1-3 can be ignored. This would mean that only crucial calculations are for years 4 and 5.