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Medium|   Algebra|      
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Sajjad1994
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­x(x-2)/[(x+3)(x-4)]^2= 0, Quantity A: x, Quantity B: -2 30 Aug 2024, 04:44
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Difficulty:

25% (medium)

Question Stats:

80% (01:30) correct 20% (01:34) wrong based on 5 sessions

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\(\frac{­x(x-2)}{[(x+3)(x-4)]^2} = 0\)

Quantity A
x

Quantity B
-2­
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A
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­x(x-2)/[(x+3)(x-4)]^2= 0, Quantity A: x, Quantity B: -2 04 Oct 2025, 20:41
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x can't be -3 or 4 coz denominator can't be 0
x=0 and x=2
both are greater than -2
Hence, A