Let's use
weighted averagesWeighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...There are more than twice as many employees in Department X as in Department YLet's see what happens if there are
EXACTLY twice as many employees in Department X as in Department Y
So, for every 3 employees, 2 work for Department X and 1 works for Department Y
In other words,
2/3 of the employees work for Department X
And
1/3 of the employees work for Department Y
The average (arithmetic mean) salary is $25,000 for the employees in Department X and $35,000 for the employees in Department YSo, the average salary of ALL employees = (
2/3)(
$25,000) + (
1/3)(
$35,000)
≈
$28,333So, the average salary of all employees =
$28,333 if there are
EXACTLY twice as many employees in Department X as in Department Y
Now let's see what happens if we MAXIMIZE the number of employees working for Department X
Let's say that
ALL of the employees work for Department X
So,
1/1 employees work for Department X, and
0/1 employees work for Department Y
Now, the average salary of ALL employees = (
1/1)(
$25,000) + (
0/1)(
$35,000)
≈
$25,000So, the average salary of all employees =
$25,000 if there
ALL of the employees work in Department X
Now that we've examined the EXTREME cases, we know that the average salary of all employees is BETWEEN
$25,000 and
$28,333Answer: A, B