surendar26
A number 'b' is formed by reversing the 2-digit number 'a'.What are the digits of 'a' ?
1. Diff. of a and b lies b/w 70 and 80.
2. 'b' is a two digit number.
A number B is formed by reversing the two digit number A. What are the digits of A? Every 2-digit number can be expressed as \(10x+y\), where \(x\) will be the tens digit (so between 1 and 9, note it can not be zero as in this case number won't be 2-digt anymore) and \(y\) will be the units digit (so between 0 and 9).
Given: \(a=10x+y\) and \(b=10y+x\).
(1) Difference of A and B lies between 70 and 80 --> \(70<(10x+y)-(10y+x)<80\) --> \(70<9(x-y)<80\) --> there is only one multiple of 9 in this range - 72, so \(9(x-y)=72\) --> \(x-y=8\) --> either \(x=9\) and \(y=1\) or \(x=8\) and \(y=0\), so either \(a=91\) or \(a=80\). Not sufficient.
(2) B is a two digit number --> just tells that \(y>0\). Not sufficient.
(1)+(2) As \(y>0\) then \(x=9\) and \(y=1\), so \(a=91\). Sufficient.
Answer: C.