Four points that form a polygon lie on the circumference of the circle. What is the area of the polygon ABCD
(1) The radius of the circle is \(\frac{\sqrt{2}}{2}\)
(2) ABCD is square.
The figure is drawn in such a way that the two angles are shown to be right angles.
Kaplan book says both statements are required to solve, but i think that state 1 alone is sufficient.
Given that we know the angle is a right angle and that a diagonal AC is joined as well. We can say that AC is a diameter (angle inscribed in a semi circle). And if we join point D with say centre O, OA OD And OC will be equal. We already know the radius. OD will be perpendicular to the base (diameter AC) and hence we can get the area. We dont need to know whether ABCD is square or not.
Could someone shed some light ?
Edit: Apologies for amateur fine art skills
Thanks
Attachments

Untitled.png [ 3.68 KiB | Viewed 6671 times ]
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.