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Solution



Steps 1 & 2: Understand Question and Draw Inferences

    • We know that a number in the form of 2k + 1 leaves a remainder of 1 when divided by 2, (that is, a number that leaves a remainder of 1 when divided by 2) is odd.
    • So, we are asked to find if the number of factors of x is odd.

To Find: Is the number of factors of x odd?

    • We know that if a number has odd number of factors, it has to be a perfect square. So, we are (indirectly) asked to find if x is a perfect square?

Step 3: Analyze Statement 1 independently

    1. √12x is an integer
    \(\sqrt{12\mathrm x}=\;\sqrt{2^2\ast3\mathrm x}=\;2\surd3\mathrm x\) is an integer. For √3x to be an integer, x should contain an odd power of 3.

    Now, if 3 occurs odd number of times in x, x can’t be a perfect square.

Hence statement-1 is sufficient to answer the question.


Step 4: Analyze Statement 2 independently

    2. The product of √x and √y is an integer, where the total number of factors of y/3 is odd.
    Statement-2 tells us that the total number of factors of \(\frac{\mathrm y}3\) is odd i.e. \(\frac{\mathrm y}3\) is a perfect square. Let’s assume \(\frac{\mathrm y}3=\mathrm z^2\), where z is an integer.

    \(y = 3z^2\). Since \(z^2\) is always non-negative, y will also be a non-negative integer
    So, we know that \(\surd\mathrm x\operatorname{ *}\;\surd3\mathrm z^2\) is an integer i.e. z√3x is an integer.
    For √3x to be an integer, x should contain an odd power of 3. If 3 occurs odd number of times in x, x can’t be a perfect square

Hence statement-2 is sufficient to answer the question.

Step 5: Analyze Both Statements Together (if needed)

Since we have a unique answer from steps 3 and 4, this step is not required.

Answer: D


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in Analyzing statment 1 Square root 3 * x X should have odd power have 3 to get an integer. How to get an integer x square root 3 should be multiplied atleast once by square root 3 to get the value of 3? 3^1/2 * 3^1/2 = 3 in the solutioon mentioned 3^1/2*3^3 = 3^7/2 is there some logic which is missing?
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Can the total number of integers that divide x be expressed in the form of \(2k + 1\), where k is a positive integer?

(1) \(√12x\) is an integer
(2) The product of \(√x\) and \(√y\) is an integer, where the total number of factors of \(\frac{y}{3}\) is odd.

in Analyzing statment 1 Square root 3 * x X should have odd power have 3 to get an integer. How to get an integer x square root 3 should be multiplied atleast once by square root 3 to get the value of 3? 3^1/2 * 3^1/2 = 3 in the solutioon mentioned 3^1/2*3^3 = 3^7/2 is there some logic which is missing?

Your doubt is poorly formatted and thus is not entirely clear. The key point is: for √12x to be an integer, 12x must be a perfect square. So x must supply the missing prime factors to make that true.

Pure algebraic questions are no longer a part of the DS syllabus of the GMAT.

DS questions in GMAT Focus encompass various types of word problems, such as:

  • Word Problems
  • Work Problems
  • Distance Problems
  • Mixture Problems
  • Percent and Interest Problems
  • Overlapping Sets Problems
  • Statistics Problems
  • Combination and Probability Problems

While these questions may involve or necessitate knowledge of algebra, arithmetic, inequalities, etc., they will always be presented in the form of word problems. You won’t encounter pure "algebra" questions like, "Is x > y?" or "A positive integer n has two prime factors..."

Check GMAT Syllabus for Focus Edition

You can also visit the Data Sufficiency forum and filter questions by OG 2024-2025, GMAT Prep (Focus), and Data Insights Review 2024-2025 sources to see the types of questions currently tested on the GMAT.

So, you can ignore this question.

Hope it helps.­
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