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10 Apr 2018, 06:35
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D
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Difficulty:
45%
(medium)
Question Stats:
66% (01:29) correct
34%
(01:48)
wrong
based on 173
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If N = 100x + 10y + z is a three-digit positive integer, is N divisible by 9?
(1) x + y + z =18
(2) N + 432 is divisible by 9.
(1) x + y + z =18
(2) N + 432 is divisible by 9.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
Updated on: 10 Apr 2018, 10:00
Originally posted by kunalcvrce on 10 Apr 2018, 09:06.
Last edited by kunalcvrce on 10 Apr 2018, 10:00, edited 1 time in total.
Last edited by kunalcvrce on 10 Apr 2018, 10:00, edited 1 time in total.
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Bunuel
From 1:
three digit number: xyz=100x + 10y + z
a number is divisible by 9, if sum of all of it digits is divisible by 9
x + y + z =18
it is divisible by 9
sufficient
From 2:
432 is divisible by 9 and N +432 is divisble by 9 so
N is divisible by 9
so sufficient.
hence D
shoumkrish
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10 Apr 2018, 09:56
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(1) x+y+z = 18
Since 100x + 10y + z is a three-digit number, each of the digit x,y and z is less than 9, hence N would be of the form xyz, which is divisible by 9.
Sufficient.
(2) N+432 is divisible by 9, since 432 is divisible by 9, hence N must also be divisible by 9.
Sufficient.
(D)
Since 100x + 10y + z is a three-digit number, each of the digit x,y and z is less than 9, hence N would be of the form xyz, which is divisible by 9.
Sufficient.
(2) N+432 is divisible by 9, since 432 is divisible by 9, hence N must also be divisible by 9.
Sufficient.
(D)
