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Interesting question because it tests the basics of the topic LCM & HCF.

Two concepts that are tested are: 1) Smallest positive factor of a positive integer will always be 1 and 2) largest positive factor of a positive integer will always be the number itself

Statement 1: Given that GCF of 1 and x is odd, does not tell us anything about the number x. This is because whether x is odd or even, GCF between the number and 1 will always be 1 (i.e. odd). Hence, this statement is insufficient

Statement 2: Given that LCM of 1 and x is even shows that x is definitely even. This is because LCM between a number and 1 is essentially x*1=x. Since this LCM is even, it proves that x is even.
Hence, this statement is insufficient

Hence, answer is B
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Bunuel

GMAT CLUB'S FRESH QUESTION



Is a positive integer x odd?

(1) The greatest common factor of the smallest positive factor of x and the largest positive factor of x is odd
(2) The least common multiple of the smallest positive factor of x and the largest positive factor of x is even

M36-26

Official Solution:


Is a positive integer \(x\) odd?

(1) The greatest common factor of the smallest positive factor of \(x\) and the largest positive factor of \(x\) is odd

The smallest positive factor of any positive integer is 1 and the largest positive factor of any positive integer is the integer itself. So, we are given that the greatest common factor of 1 and \(x\) is odd. This is true for any positive integer \(x\) because the greatest common factor of 1 and \(x\) is always 1, which is odd. So, \(x\) could be any positive even or any positive odd number. Not sufficient.

(2) The least common multiple of the smallest positive factor of \(x\) and the largest positive factor of \(x\) is even

The smallest positive factor of any positive integer is 1 and the largest positive factor of any positive integer is the integer itself. So, we are given that the least common multiple 1 and \(x\) is even. Since the least common multiple 1 and \(x\) is \(x\) itself, then we are basically told that \(x\) is even. Sufficient.


Answer: B
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