amanvermagmat
Two parallel lines L1 and L2 lie in a plane at a perpendicular distance of 5 units from each other. A triangle ABC is drawn such that points A, B lie on L1 while point C lies on L2. Similarly a parallelogram PQRS is also drawn such that points P, Q lie on L1 while points R, S lie on L2. What is the ratio of area of triangle ABC to that of parallelogram PQRS?
(1) PQ = 3 units.
(2) AB = PQ.
2 parallel line L1 and L2 and a distance between them is 5 units.
Area of triangle ABC
= 1/2 * AB (base) * height (lets call it MN) = 5/2*ABArea of parallelogram
= MN * PQ =5*PQWe need to find the ratio of areas of ABC and PQRS.
Statement 1: PQ = 3 units.
Clearly insufficient.
Statement 2: AB = PQ
Area of ABC =5/2*AB = 2.5*(AB) and Area of PQRS = 5*PQ
Ratio of areas = Area of ABC / Area of PQRS =
2.5*AB / 5*PQSince AB = PQ; Ratio of areas =
2.5/5 = 1/2.
Therefore, Statement 2 is Sufficient. Answer: B