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13 Jul 2018, 10:59
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
65% (02:02) correct
35%
(01:58)
wrong
based on 162
sessions
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Truck A gives an average of X miles per gallon of petrol while truck B gives an average of Y miles per gallon of petrol. Both trucks travelled from a city to another, covering a distance of 1500 miles each in this process. What is the difference in the number of gallons of petrol used by the two trucks, for this 1500 mile trip.
(1) X is 20% less than Y.
(2) Y - X = 5.
(1) X is 20% less than Y.
(2) Y - X = 5.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
13 Jul 2018, 12:42
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amanvermagmat
Avg MPG=Total Miles driven/Total No of gallons used
No of gallons of Truck A used=Miles driven by A/MPG=\(\frac{1500}{X}\)
No of gallons of Truck B used=Miles driven by A/MPG=\(\frac{1500}{Y}\)
So, Difference in the number of gallons of petrol used by the two trucks=\(\frac{1500}{X}-\frac{1500}{Y}\)
St1:-X is 20% less than Y.
Or, X=Y(1-0.2)=0.8Y
One equation two variables, so, we can't determine X and Y. hence insufficient.
St2:-Y - X = 5
One equation two variables, so, we can't determine X and Y. hence insufficient.
Combining , we have,
X=0.8Y & Y - X = 5
So,we can determine X & Y, and subsequently the difference in nos. of gallons.
Ans. (C)
13 Jul 2018, 12:44
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amanvermagmat
According to the Q-stem : A uses 1500/X gallons of petrol & A uses 1500/Y gallons of petrol
Hence the difference in petrol used : 1500/X- 1500/Y =1500(1/X - 1/Y)= 1500{(Y-X)/XY} ........expression 1
Statement 1==> X is 20% less than Y => X=0.8Y Hence, expression 1 ==> 1500{(Y-0.8Y)/0.8Y*Y}........On simplification a factor of Y remains........Not Sufficient
Statement 2==>Y - X = 5 Hence, expression 1 ==> 1500*{5/X*(X+5)}=12.............................Not Sufficient
Statement 1 & 2==> Y=25 & X=20 ..... Thus in expression 1 ==>1500{(25-20)/25*20} ..............Sufficient ....... Hence I would go for option C.
