If e is a nonzero integer, is 1/2^e greater than or less than 1?

Question

(1) −e < 1
(2) e^2 > 0

sumi747 · Answer

If e is less than 0 the value of 1/2^e can be greater than 1
1. E>-1
So e>=1
1/2^e greater than 1--> no
So statement 1 is giving us the answer to the question 
2. E^2>0
E can be either negative or positive
So statement 2 is not sufficient to ans the question

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Archit3110 · Answer

#1 -e<1 means e=-ve integer so 1/2^e will always be >1 sufficient #2 e^2 > 0 e can be +ve or -ve so 1/2^e can be > 1 or <1 ; not sufficient IMO A

ocelot22 · Answer

(1) −e < 1 (2) e^2 > 0 Ok (1/2) ^ e, where e does not equal 0 and e is an integer will be greater than 1 if e <0 (a fraction to a negative exponent gives us 1 divided by some number less than 1, and thus we get a number greater than 1). So the question simplifies to is e <0 subject to the constraint e is an integer >0 Yes/No? (1) -e <1 gives us e >-1 |e is an integer not equal to 0 --> This means that e = 1,2,3, thus e>0, thus we can mark sufficient. (2) e^2 >0. Therefore either e>0 or e <0 | e is an integer not equal to 0. First consider e >0. Then e = 1,2,3... thus we get a YES answer. Now lets consider e <0 | e is an integer not equal to 0. Then e = -1,-2,-3...., thus e <0 giving us a NO answer. Thus (2) is NS

Archit3110 · Answer

ocelot22

Please see question :  e is a nonzero integer 
in #1 you have considered e as a fraction....

ocelot22 · Answer

Fixed

mokiburnsred · Answer

At the end of #1 you say means e=-ve integer.
Shouldn't it be the other way around (e=+ve integer)?
But the answer remains same for either of them. Just wanted to clarify..

If e is a nonzero integer, is 1/2^e greater than or less than 1?

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