|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
06 Sep 2019, 10:51
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
47% (02:03) correct
53%
(01:42)
wrong
based on 49
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of \(\frac{x + 3y - 10z}{a + 3b - 10c}\) ?
(1) \(\frac{x}{a} = \frac{y}{b} = \frac{z}{c}\)
(2) \(x = 2y = 3z\)
(1) \(\frac{x}{a} = \frac{y}{b} = \frac{z}{c}\)
(2) \(x = 2y = 3z\)
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
07 Sep 2019, 02:10
Kudos
Bookmarks
What is the value of \(\frac{x+3y−10z}{a+3b−10c}\)?
STATEMENT-(1) \(\frac{x}{a}\)=\(\frac{y}{b}\)=\(\frac{z}{c}\)
let \(\frac{x}{a}\)=\(\frac{y}{b}\)=\(\frac{z}{c}\) = t
x =at, y =bt, and z=ct
value of \(\frac{x+3y−10z}{a+3b−10c}\) = \(\frac{t(a+3b-10c)}{a+3b-10c}\) = t
we don't know the value of t so we cant find the value of \(\frac{x+3y−10z}{a+3b−10c}\)
hence, INSUFFICIENT
STATEMENT-(2) x=2y=3z
We don't know anything about a ,b and c hence
this statement is INSUFFICIENT
combining both--STATEMENT-(1)&STATEMENT-(2)
let \(\frac{x}{a}\)=\(\frac{y}{b}\)=\(\frac{z}{c}\) = t
x =at, y =bt, and z=ct
and x=2y=3z
at = 2bt = 3ct (still we cant find the value of t --t can be any value)
value of \(\frac{x+3y−10z}{a+3b−10c}\) = \(\frac{t(a+3b-10c)}{a+3b-10c}\) = t
we cant find the value of t
so we cant find the value of \(\frac{x+3y−10z}{a+3b−10c}\)
hence, INSUFFICIENT
E is the correct answer
STATEMENT-(1) \(\frac{x}{a}\)=\(\frac{y}{b}\)=\(\frac{z}{c}\)
let \(\frac{x}{a}\)=\(\frac{y}{b}\)=\(\frac{z}{c}\) = t
x =at, y =bt, and z=ct
value of \(\frac{x+3y−10z}{a+3b−10c}\) = \(\frac{t(a+3b-10c)}{a+3b-10c}\) = t
we don't know the value of t so we cant find the value of \(\frac{x+3y−10z}{a+3b−10c}\)
hence, INSUFFICIENT
STATEMENT-(2) x=2y=3z
We don't know anything about a ,b and c hence
this statement is INSUFFICIENT
combining both--STATEMENT-(1)&STATEMENT-(2)
let \(\frac{x}{a}\)=\(\frac{y}{b}\)=\(\frac{z}{c}\) = t
x =at, y =bt, and z=ct
and x=2y=3z
at = 2bt = 3ct (still we cant find the value of t --t can be any value)
value of \(\frac{x+3y−10z}{a+3b−10c}\) = \(\frac{t(a+3b-10c)}{a+3b-10c}\) = t
we cant find the value of t
so we cant find the value of \(\frac{x+3y−10z}{a+3b−10c}\)
hence, INSUFFICIENT
E is the correct answer
Moderator:
