Bunuel
Is \(\sqrt{\sqrt[n]{m\) an integer?
(1) m = n + 14
(2) m = 5n + 6
We need to answer the question:
Is root[2n] of m = integer ?
Statement One Alone:=> m = n + 14
If n = 2, then root[2n] of m = root[4] of 16 = 2, which is an integer.
Whereas, if n = 1, then root[2n] of m = root[2] of 15, which is not an integer.
Statement one is not sufficient. Eliminate answer choices A and D.
Statement Two Alone:=> m = 5n + 6
If n = 2, then root[2n] of m = root[4] of 16 = 2, which is an integer.
Whereas, if n = 1, then root[2n] of m = root[2] of 11, which is not an integer.
Statement two is not sufficient. Eliminate answer choice B.
Statements One and Two Together:The two statements together are sufficient to determine the values of m and n:
5n + 6 = n + 14
4n = 8
n = 2 and m = 16, so root[2n] of m = root[4] of 16 = 2, which is an integer.
The two statements together are sufficient.
Answer: C