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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
39% (02:05) correct
61%
(02:01)
wrong
based on 76
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(p > q\)?
1. \(\sqrt{q} > p\)
2. \(q^{3} >p\)
1. I really liked this question and hence sharing it here with the larger group
2. Do give it a shot and share your approach. I will share my approach as well
3. Source - Experts' Global
1. \(\sqrt{q} > p\)
2. \(q^{3} >p\)
1. I really liked this question and hence sharing it here with the larger group
2. Do give it a shot and share your approach. I will share my approach as well
3. Source - Experts' Global
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
15 Aug 2020, 08:39
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Pritishd
Option A - Insufficient
1. \(q\) will be positive because root of a negative integer is not possible
2. Say \(q = 4\) then \(\sqrt{q}\) \(= 2\) then \(p\) can be 1, 0... and \(p < q\)
3. Say \(q = \frac{1}{4}\) then \(\sqrt{q}\) \(= \frac{1}{2}\) then \(p\) can be \(\frac{1}{3}\) and \(p > q\)
Option B - Insufficient
1. Say \(q = 3\) then \(q^3\) \(= 27\) then \(p\) can be 26 and \(p > q\)
3. Say \(q = \frac{1}{2}\) then \(q^3\) \(= \frac{1}{8}\) then \(p\) can be \(\frac{1}{9}\) and \(p < q\)
Combining both statements, we get:-
1. \(q\) is positive
2. If \(q\) is an positive integer then \(q^3 > q > \sqrt{q} > p\)
3. If \(q\) is a positive fraction then \(\sqrt{q} > q > q^3 > p\)
4. \(q\) will always be greater than \(p\)
Ans. C
15 Aug 2020, 09:05
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Pritishd
This is the same exact question as the following one: https://gmatclub.com/forum/is-x-y-1-x-1 ... 00636.html
