Is X an even integer ?

Question

A. When X is divided by 7 the remainder is 1
B. X is the median of all odd integers below 100

kudos for detailed explanation with correct answer

ArunSharma12 · Answer

statement 1:
X = 7k + 1
possible values of X:  
X can be even or odd
not sufficient

statement 2:
X = median(1,3,...,99)
X = 51 + 53 / 2 = 52
X is even
sufficient

ans: B

AnisMURR · Answer

The median is not equal to 52

IanStewart · Answer

Statement 1 is not sufficient, since x can be 8 or 15.

Statement 2 doesn't make sense, since there is an infinite number of odd integers less than 100. If the Statement meant only the positive odd integers, then of course it's sufficient, since we know exactly what those integers are, and could calculate their median if we needed to. There's no reason to actually find that median on a DS question, but if we wanted to, then because the odd integers from 1 through 99 form an equally spaced list, the median will equal the average of the smallest and largest terms, which is 50.

TestPrepUnlimited · Answer

Statement 1:

x = 8, 15, 22 ... then x doesn't have to be even so insufficient.

Statement 2:

The statement probably meant "positive odd integers". Thus we are including 1, 3, 5 ..., 97, 99. The set is fixed so the median X is fixed, sufficient.

Ans: B

VoltAmpere · Answer

Is X an even integer ?

Statement 1: When X is divided by 7 the remainder is 1
X can be {1,8,12,22,29...}. -can be even or odd  NOT SUFFICIENT

Statement 2:X is the median of all odd integers below 100
Since the median of all odd integers below 100 (assuming positive only) is fixed, i.e. only one answer -we need not to determine the value, but we can determine if its odd or even.  SUFFICIENT

CORRECT ANSWER: B

Is X an even integer ?

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