A, B, C, D and E are five distinct positive integers such that D is th

Question

A, B, C, D and E are five distinct positive integers such that D is the average of A and E. Is C the largest of the five integers?

(1) A − E is negative, and B is not the smallest of the five integers.
(2) E − C is negative, and B is not the largest of the five integers.

TestPrepUnlimited · Answer

Since all integers are distinct, we can conclude  E > D > A  or  A > D > E  since D is the average. Is C the largest?

Statement 1:

Nothing on C so insufficient. This gives us  E > A , thus  E > D > A  and possibly  B > A .

Statement 2:

C > E . But we don't know if E is larger than A so we may have  A > D > E . Insufficient.

Combined:

From statement 1  E > D > A  and combined with statement 2  C > E >D > A . We know B is not the largest integer so it must be C that is the largest. Sufficient.

Ans: C

A, B, C, D and E are five distinct positive integers such that D is th

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