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What is the value of x?

(1) |x + 9| = 2x.

The left hand side is an absolute value, so it cannot be negative, thus the right hand side also cannot be negative, which means that x is positive or 0. If \(x \geq 0\), then x + 9 > 0, thus |x + 9| = x + 9. So, we'd have that x + 9 = 2x. Solving gives x = 9. Sufficient.

(2) |2x − 9| = x.

2x - 9 = x --> x = 9. Plug back to verify this solution: |2*9 - 9| = 9 --> OK;
2x - 9 = -x --> x = 3. Plug back to verify this solution: |2*3 - 9| = 3 --> OK.

Not sufficient.

Note that we cannot use trick we used for (1) for (2): yes, |2x − 9| = x also implies that x must be positive but 2x - 9 could be positive as well as negative for positive x.


Answer: A.
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#1
|x + 9| = 2x
solve we get x=9 & -3
LHS cannot be -ve so -3 is not possible x=9 sufficient
#2
|2x − 9| = x
x=9,3
two values of x insufficient
option A is correct


Bunuel
What is the value of x?

(1) |x + 9| = 2x

(2) |2x − 9| = x
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Hi Bunuel,
I have a question about the solution you mentioned above. Why did we straight away take positive value for the first statement and not for the second one? The second statement has the same structure as the first one.

|2x -9 | = x, what if I move forward the same way as in statement 1. That is: x is positive and |2x-9| is an absolute value, hence always positive. Therefore
> |2x - 9| = x
> 2x - 9 = x
> x = 9.

What am I getting wrong here?
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deeuce
Hi Bunuel,
I have a question about the solution you mentioned above. Why did we straight away take positive value for the first statement and not for the second one? The second statement has the same structure as the first one.

|2x -9 | = x, what if I move forward the same way as in statement 1. That is: x is positive and |2x-9| is an absolute value, hence always positive. Therefore
> |2x - 9| = x
> 2x - 9 = x
> x = 9.

What am I getting wrong here?

You are right to deduce that |2x -9 | = x implies that x must be more than or equal to 0. But |2x - 9| = 2x - 9 ONLY IF 2x - 9 >= 0 and x >= 0 does not necessarily means that 2x - 9 >= 0. For example, if x = 1, then 2x - 9 = -7. So, for some positive values of x, 2x - 9 will be positive and for some positive values of x, 2x - 9 will be negative. This is why we cannot use the same technique for (2) as we used for (1).

Hope it's clear.
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