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05 May 2021, 08:00
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
65% (01:08) correct
35%
(01:18)
wrong
based on 71
sessions
History
Date
Time
Result
Not Attempted Yet
Are a and b both integers?
(1) \(a^2 + b^2\) is an integer.
(2) \(\frac{a}{b}\) is an integer.
(1) \(a^2 + b^2\) is an integer.
(2) \(\frac{a}{b}\) is an integer.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
05 May 2021, 08:12
Kudos
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Are a and b both integers?
Stat1: a^2+b^2 is an integer.
Not sufficient as a and b can be square root.
Stat2: a/b is an integer.
again Not sufficient as a and b can be square root, e.g. a = 8^1/2, b= 2^1/2
Combining both, Still a and b can be square root values. Not sufficient.
So, I think E
Stat1: a^2+b^2 is an integer.
Not sufficient as a and b can be square root.
Stat2: a/b is an integer.
again Not sufficient as a and b can be square root, e.g. a = 8^1/2, b= 2^1/2
Combining both, Still a and b can be square root values. Not sufficient.
So, I think E
26 Sep 2021, 07:07
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Bunuel
Very good question Bunuel!
S1: \(a^2 + b^2\) is an integer [Insufficient]
1. If \(a = 2\) and \(b = 3\) then \(a^2 + b^2\) is an integer, and \(a\) and \(b\) are both integers
2. If \(a =\) \(\sqrt{2}\) and \(b = 3\) then \(a^2 + b^2\) is an integer, but \(a\) and \(b\) both are not integers
S2: \(\frac{a}{b}\) is an integer [Insufficient]
1. If \(a = 4\) and \(b = 2\) then \(\frac{a}{b}\) is an integer, and \(a\) and \(b\) are both integers
2. If \(a =\) \(\sqrt{8}\) and \(b =\) \(\sqrt{2}\) then \(\frac{a}{b}\) is an integer, but \(a\) and \(b\) both are not integers
S1 + S2 [Insufficient]
1. If \(a = 4\) and \(b = 2\) then \(a^2 + b^2\) and \(\frac{a}{b}\) are integers, and \(a\) and \(b\) are both integers
2. If \(a =\) \(\sqrt{8}\) and \(b =\) \(\sqrt{2}\) then \(a^2 + b^2\) and \(\frac{a}{b}\) are integers, but \(a\) and \(b\) both are not integers
Ans. E
