From statement I alone, \(y^2\) > 4.
Therefore, \(y^2 – 4\) > 0 OR (y-2) (y+2) > 0.
The solutions for the above quadratic inequality are y>2 OR y< -2. One of the ranges can give a YES to the question and the other gives a NO.
Statement I alone is insufficient. Answer options A and D can be eliminated. Possible answer options are B, C or E.
From statement II alone, \(y^2\) > 16.
Therefore, \(y^2\) – 16 > 0.
The solutions for the above quadratic inequality are y>4 OR y< -4. One of the ranges can give a YES to the question and the other gives a NO.
Statement II alone is insufficient. Answer option B can be eliminated. Possible answer options are C or E.
Combining statements I and II, we have the following:
From statement I alone, y>2 OR y< -2
From statement II alone, y>4 OR y< -4.
The common range for both is y>4 OR y< -4, which is still insufficient to answer the question with a YES or NO.
The combination of statements is insufficient to answer the question. Answer option C can be eliminated.
The correct answer option is E.
Hope that helps!
Aravind B T