|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
29 Sep 2021, 01:00
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
36% (02:41) correct
64%
(02:31)
wrong
based on 137
sessions
History
Date
Time
Result
Not Attempted Yet
M is a positive integer, what is the greatest common factor of M and 64?
(1) No two different factors of M sum to a prime number.
(2) The greatest common factor of M and 2,310 is 165.
(1) No two different factors of M sum to a prime number.
(2) The greatest common factor of M and 2,310 is 165.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
10 Oct 2021, 08:30
Kudos
Bookmarks
Bunuel
\(64 = 2^6 \) Hence \(64\) has \(6+1 = 7\) factors i.e. \(1, 2, 4 ,8 ,16, 32, 64\)
(1) No two different factors of M sum to a prime number. =
Remember \(1\) is a factor of every number, Now M cannot have \(2\) as a factor because \(1+2 = 3 \) which is a prime number. If M does not have a \(2 \) , it cannot have \(2, 4 ,8 ,16, 32, 64 \) as factors .
Hence HCF of M and \(64 \) can be \(1\) only.
SUFF.
(2) The greatest common factor of M and \(2,310\) is \(165\)
\(2310= 2*3*5*7*11\)
HCF of M and \(2310 ->165 =3*5*11 \)
This shows that M does not have \(2\) as a factor , because if it did , HCF of M and \(2310\) would include a \(2\) .
If M does not have a 2, it cannot have \(2,4 ,8 ,16, 32, 64\) as factors.
Hence HCF of M and \(64 \) can be \(1\) only.
SUFF.
Ans D
Hope it's clear
03 Nov 2021, 07:11
Kudos
Bookmarks
