Bunuel
If a, b and x are integers such that \(a^6=b^3=\frac{|x|}{x}\), what is the value of a-b ?
(1) \(a^3*b^7>0\)
(2) \(a+b>0\)
\(a^6=b^3=\frac{|x|}{x}\)
Inference: \(\frac{|x| }{ x}\) can either be 1 or -1. Its given that \(\frac{|x| }{ x}\) = \(a^6\), hence the value of \(\frac{|x|}{x}\) cannot be negative. Thus \(\frac{|x| }{ x}\) = 1.
With that pre-thinking, let see if we can infer anything further
\(a^6 = 1\); so 'a' can be +1 or -1.
\(b^3\) = 1; therefore 'b' = 1Questiona-b = ?
We already know the value of a, hence if we can know the value (rather positive negative nature) of a, we can answer the question.
Statement 1\(a^3*b^7>0\)We already know b = 1, so if \(a^3*b^7>0\) then a is positive. Hence a = 1.
The statement is sufficient to answer, hence we can eliminate B, C and E.
Statement 1\(a+b>0\)As b = 1, a cannot be -1 otherwise the sum will be 0 and not greater than 0. So a = 1.
This statement is also sufficient.
Option D