Bunuel

In the above figure, what is the area of the circle with center C?
(1) The length of minor arc AB is one-sixth of the circumference.
(2) The length of chord AB is 8.
Solution: Pre Analysis:- We are asked about the area of the given circle
- So, we basically need the radius of the circle
Statement 1: The length of minor arc AB is one-sixth of the circumference
- Let us assume \(\angle ACB=\theta\)
- Accordign to this statement, \(\frac{\theta}{360}\times 2\pi r=\frac{1}{6}2\pi r\) or \(\theta=60^o\)
- We already know that \(\angle CAB=\angle CBA\) because they are opposite to equal sides which are radius
- Thus we can infer that \(AB=BC=CA\)
- But we still do not get the value of AC or CB or radius
- Thus, statement 1 alone is not sufficient and we can eliminate options A and D
Statement 2: The length of chord AB is 8
- Knowing the length of the chord will not help us get the radius
- Thus, statement 2 alone is also not sufficient
Combining: - From statement 1, we get \(AB=BC=CA\)
- From statement 2, we get \(AB=8\)
- After combining, we get the length of radius \(AC=CB=8\)
Hence the right answer is
Option C