Bunuel
If x, y are positive integers, is \(xy=1\)?
(1) \(x^2y^2=xy\)
(2) \(\frac{1}{y}=x\)
Solution: Pre Analysis:- x, y are positive integers
- We are asked if \(xy=1\) or not
Statement 1: \(x^2y^2=xy\)
- Inference:
- We have \((xy)^2=xy\) which means its square of positive integer is equal to the same positive integer
- This is true only when the positive integer is 1
- Thus, \(xy=1\)
- Algebra 1:
- We have \(x^2y^2=xy\)
- Since x and y are positive integers, we can cancel them from opposite sides of equal to sign and say \(xy=1\)
- Algebra 2:
- We have \(x^2y^2=xy\)
\(⇒x^2y^2-xy=0\)
\(⇒xy(xy-1)=0\) - Either \(xy=0\) which is not possible because x and y are positive integers
- Or \(xy=1\)
- Thus, statement 1 alone is sufficient and we can eliminate options B, C and E
Statement 2: \(\frac{1}{y}=x\)
- We can multiply positive integer y to both the sides and get \(xy=1\)
- Thus, statement 2 alone is also sufficient
Hence the right answer is
Option D