Bunuel
2a3 is a 3-digit positive integer. If 2a3 + 366 = 6b9, what is the value of a + b ?
(1) 2a3 is divisible by 3.
(2) 6b9 is divisible by 9.
We can use the place value concept to make the original equation more accessible:
2a3 + 366 = 6b9
(203 + 10a) + 366 = (609 + 10b)
10a = 10b + 40
a = b + 4
We need to answer the question:
a + b = ?
Statement One Alone:=> 2a3 is divisible by 3.
An integer is divisible by 3 if and only if the sum of its digits is divisible by 3, so
2 + a + 3 is div by 3, or a + 5 is div by 3
If a is 1, then b is -3 (= 1 – 4), which is not a valid case.
If a is 4, then b is 0 (= 4 – 4) and a + b = 4.
If a is 7, then b is 3 (= 7 – 4) and a + b = 10.
Statement one is not sufficient. Eliminate answer choices A and D.
Statement Two Alone:=> 6b9 is divisible by 9.
An integer is divisible by 9 if and only if the sum of its digits is divisible by 9, so
6 + b + 9 is div by 9, or b + 15 is div by 9
In the only valid case, b is 3, a is 7 (= 3 + 4), and a + b is 10.
Statement two is sufficient.
Answer: B