What is the median of 3 consecutive integers?
(1) The product of the integers is 0
Let three consecutive integers be (n-1), n, and (n+1)
(n-1)n(n+1)= n(n^2-1)=0
Either n =0. In this case, integers are -1,0,1 and median is 0
OR
n^2-1=0
n^2=1
n=1, integers are 0,1,2 and median is 1
n=-1, integers are -2, -1, 0 and median is -1.
A unique value of median can't be determined.
Statement I alone is insufficient.
(2) The sum of the integers and the product of the integers are the same.
n-1+n+n+1= 3n=n (n^2-1)
n^2-1=3
n^2=4
n=2, integers are 1,2,3 and median is 2.
n=-2, integers are -3,-2,-1 and median is -2.
Statement II alone is not sufficient.
Combining statement I and statement II
The only possible consecutive integers the product of which is 0 and sum=product are -1,0, and 1 with median = 0.
Correct answer is option C.
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