Bunuel
If x^2 - y^2 = 1, what is the value of x?
(1) x + y = 1/2
(2) y^2 = 9/16
\(x^2 - y^2 = 1\)
\((x+y)(x-y) = 1\)
Statement 1(1) x + y = 1/2This statement provides us with the value of x + y. Using the premise we can obtain the value of x - y.
Using both equations, we can find the value of x.
We need not solve the equation in its entirety as this is a DS question, but we do have enough information to solve and find the value of x.
The statement alone is sufficient, and we can eliminate B, C, and E.
Statement 2(2) y^2 = 9/16Using this statement we can find the value of \(x^2\).
\(x ^ 2 = 1 + \frac{9}{16}\)
However, when we take the square root on both sides, we will get two values of x, one positive and one negative. Because we can have multiple possible values of x, this statement alone is not sufficient. We can eliminate D.
Option A