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08 Oct 2023, 05:15
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:35) correct
35%
(01:47)
wrong
based on 37
sessions
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Not Attempted Yet
If \(wx>0\), \(xy>0\), and \(yz<0\), is \(w^3*z^2<0\) ?
(1) \(z>0\)
(2) \(x<0\)
(1) \(z>0\)
(2) \(x<0\)
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
08 Oct 2023, 06:18
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Bunuel
Given
- \(wx>0\)
Inference: w & x have the same positive-negative sign. - \(xy>0\)
Inference: y & x have the same positive-negative sign. Therefore, we can conclude that x, y and w have the same positive - negative sign. - \(yz<0\)
Inference: y & z have the different positive-negative sign.
Hence, we can have two cases -
- Case 1 : x, y and w are positive; z is negative
- Case 2 : x, y and w are negative; z is positive
Question: \(w^3*z^2<0\)
\(z^2\) is non - negative, hence target question is "Is \(w\) negative" ?
Statement 1
(1) \(z>0\)
If z is greater than 0, it is positive. Hence, to satisfy the conditions mentioned in the premise, \(w\) must be negative. The statement alone is sufficient. We can eliminate B, C, and E.
Statement 2
(2) \(x<0\)
From the conditions mentioned in the premise, we inferred that \(x\) and \(w\) share the same positive - negative sign. As \(w\) is negative, \(x\) is also negative. This statement is also sufficient.
Option D
08 Oct 2023, 08:03
Kudos
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wx> 0, xy> 0, yz <0. Is w³z²<0?
St 1: If z >0, y must be negative. If y is negative, x must also be negative. If x is negative, w must be negative as well. So we don't care about the sign of z in w³z², but w is negative so w³z² must be negative. BCE out.
St 2: If x<0, w and y must be negative too since wx and yx both are greater than 0. If w is negative so w³z² is also negative. A out.
D is the answer.
Posted from my mobile device
St 1: If z >0, y must be negative. If y is negative, x must also be negative. If x is negative, w must be negative as well. So we don't care about the sign of z in w³z², but w is negative so w³z² must be negative. BCE out.
St 2: If x<0, w and y must be negative too since wx and yx both are greater than 0. If w is negative so w³z² is also negative. A out.
D is the answer.
Posted from my mobile device
