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xALIx
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y Updated on: 08 May 2022, 02:27
Originally posted by xALIx on 19 Jan 2009, 16:45.
Last edited by Bunuel on 08 May 2022, 02:27, edited 4 times in total.
Renamed the topic, edited the question and added the OA.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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15% (low)

Question Stats:

74% (01:02) correct 26% (01:13) wrong based on 385 sessions

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Is |x| > |y| ?

(1) x^2 > y^2
(2) x > y
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A
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 19 Jan 2009, 20:15
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x-ALI-x
Is |x| > |y| ?

1) \(x^2 > y^2\)
2) x > y
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A.
1: since x^2 and y^2 both are +ve, lxl>lyl is true. suff..
2: when x>y, x could be 1 and y = -10, or x = 10 and y = -1. insuff.
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 19 Jan 2009, 23:03
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stmnt 1 : x^2 > y ^2 implies absolute value of x > absolute value of y ...sufficient.

stmnt 2: x > y if x and y both positive it gives an answer yes.
If x is positive and y negative it gives an answer No.
if x and y both negative it gives an answer No.
insufficient.


so answer is A.

www.graduatetutor.com
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 20 Jan 2009, 06:28
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graduateprofessor


stmnt 2: x > y if x and y both positive it gives an answer yes.
If x is positive and y negative it gives an answer No.
if x and y both negative it gives an answer No.
insufficient.
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That's not quite right. If x is positive and y is negative, it gives the answer 'Maybe', not 'No'. If x = 5, y = -2, then x > y and |x| > |y|. If x = 2 and y = -5, then x > y and |x| < |y|.

That doesn't affect the answer in this case, but it would be important if the question had told us, for example, that xy < 0.
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 25 Jan 2009, 18:26
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since x^2 and y^2 both are +ve, lxl>lyl
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This seems to be a rule that can be used repeatedly.
For example:
x^2 = 36
y^2 = 25
since we're only looking at the absolute value, therefore: 6 > 5. So, lxl>lyl.

Thoughts?
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 26 Jan 2009, 16:08
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x-ALI-x
Is |x| > |y| ?

1) \(x^2 > y^2\)
2) x > y

A.
1: since x^2 and y^2 both are +ve, lxl>lyl is true. suff..
2: when x>y, x could be 1 and y = -10, or x = 10 and y = -1. insuff.
Show more

I guess I could be making a really stupid question, but i've never seen the notation +ve. What does it stand for?
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x2suresh
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 26 Jan 2009, 19:18
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AdrianPeterson
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x-ALI-x
Is |x| > |y| ?

1) \(x^2 > y^2\)
2) x > y

A.
1: since x^2 and y^2 both are +ve, lxl>lyl is true. suff..
2: when x>y, x could be 1 and y = -10, or x = 10 and y = -1. insuff.

I guess I could be making a really stupid question, but i've never seen the notation +ve. What does it stand for?
Show more

+ve = positive
-ve = negative
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 16 Oct 2011, 14:11
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looks like a 500 level ques....IMO a
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 14 Sep 2016, 23:44
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x^2 > y^2 . Squaring both sides gives |x| > |y|
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 29 Oct 2020, 10:56
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Is |x| > |y| ?

(1) \(x^2 > y^2\)

Absolute value of x > y. Sufficient.

(2) x > y

We can't conclude anything with this statement. For example:

let x = -4 y = -5

\(-4 > -5\)
\(|4| < |5| \)

Answer is A.
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Is |x| > |y| ? (1) x^2 > y^2 (2) x > y 25 Apr 2024, 18:11
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