Lars1988
Can someone please help me? I really want to know how the calculation is made.
The base of a prism is an equilateral triangle with 6 cm sides, and the figure's height is perpendicular to its base. The figure is one-third full of water. The water is completely transferred into six identical cubes with 3cm sides. Each is completely full. What is the height of the now-empty prism?
Volume of the prism = Area of equilateral triangle * Height of prism
Volume of water in the prism = Area of base * (1/3)Height \(= \frac{\sqrt{3}*6^2}{4} * \frac{1}{3} * Height\)
Volume of a cube = side^3
Volume of water in all 6 cubes \(= 6 * 3^3\) (since the cubes are full of water, volume of cube = volume of water)
\(6 * 3^3 = \frac{\sqrt{3}*6^2}{4} * \frac{1}{3} * Height\)
\(\frac{4*3^4}{6*\sqrt{3}} =\)Height of cylinder
Height of cylinder\(= 18\sqrt{3}\)
Note: Just like you can visualize a cylinder as cut outs of circle stacked together to give it height, you can visualize a prism as cut outs of equilateral triangles stacked together to give it height. In such cases, volume of the solid = Area of base * Height.
Check out our geometry book for a discussion on common 3D shapes.