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# VS: value of S

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Manager
Joined: 22 Sep 2008
Posts: 119
VS: value of S [#permalink]

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05 Oct 2008, 03:37
PFA

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Intern
Joined: 04 Oct 2008
Posts: 8
Re: VS: value of S [#permalink]

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05 Oct 2008, 08:25
Start with the unit circle, a circle of radius 1 centered around the origin.

$$(-sqrt3,1)$$ is not on the unit circle, but $$((-sqrt3)/2,1/2)$$ is.

This leads me to believe that point P lies on the circle with radius 2 at 150 degrees.

150 - 90 = 60

2*(cos 60) = 1

My answer is B.
SVP
Joined: 17 Jun 2008
Posts: 1502
Re: VS: value of S [#permalink]

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05 Oct 2008, 12:45
Since OP and OQ are perpendicular to each other, multiplication of their slopes will be -1.

Or. (t/s)(1/-sqrt3) = -1 or t = (sqrt3)s.

Also, equation of circle with radius 2 is x^2 + y^2 = 4 and since, (s,t) lies on circle, hence s^2 + t^2 = 4 or s^2 + 3s^2 = 4 or s = 1 (as -1 is not the answer choice )
Senior Manager
Joined: 04 Aug 2008
Posts: 369
Re: VS: value of S [#permalink]

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05 Oct 2008, 13:31
what a tricky misleading question!

Solve this using pythagorean theorem to find P's distance from x and y intersection
distance^2=sqrt3+2= 2

Q must be equidistant and therefore 2

using 90 triangle rule calculate the hypothenus 2, 2 so 2*sqrt2

subtract sqrt3

and you get 1.096 as a solution!
_________________

The one who flies is worthy. The one who is worthy flies. The one who doesn't fly isn't worthy

Last edited by spiridon on 06 Oct 2008, 08:14, edited 2 times in total.
Manager
Joined: 30 Sep 2008
Posts: 111
Re: VS: value of S [#permalink]

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05 Oct 2008, 23:43
csvobo wrote:
Start with the unit circle, a circle of radius 1 centered around the origin.

$$(-sqrt3,1)$$ is not on the unit circle, but $$((-sqrt3)/2,1/2)$$ is.

This leads me to believe that point P lies on the circle with radius 2 at 150 degrees.

150 - 90 = 60

2*(cos 60) = 1

My answer is B.

good approach

Call <PO(-x) = <O1
<QOx = <O2

tanO1 = sqrt(3) / 1 => <O1 = 30' => <O2 = 60'

OP = OQ = sqrt (sqrt(3)^2 + 1) = 2

s = cos60 x OQ = 1/2 * 2 = 1
Manager
Joined: 22 Sep 2008
Posts: 119
Re: VS: value of S [#permalink]

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06 Oct 2008, 06:00
Hey how you guys come to know radius is '2'?

Thanks
Director
Joined: 27 Jun 2008
Posts: 525
WE 1: Investment Banking - 6yrs
Re: VS: value of S [#permalink]

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06 Oct 2008, 06:56
Left to Right - co-ordinates shift
Top to Down - Signs shift

Also, you know the signs for the below
I = a>0,b>0
II = a<0,b>0
III = a<0,b<0
IV = a<0,b<0

So, answer is 1
Manager
Joined: 22 Sep 2008
Posts: 119
Re: VS: value of S [#permalink]

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08 Oct 2008, 20:28
sorry guys.. me not expert in maths..

how to do you derive this thing "This leads me to believe that point P lies on the circle with radius 2 at 150 degrees."

3/4 +1/4 =1 i understand till this point.. unit circle. but not more that that.

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: VS: value of S   [#permalink] 08 Oct 2008, 20:28
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# VS: value of S

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