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# walker type of problem (round 2)

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Director
Joined: 01 Jan 2008
Posts: 601
walker type of problem (round 2) [#permalink]

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05 Aug 2008, 13:13
1
For any non-negative n and any real r solve equation:

$$sqrt(m) + sqrt(m+1) = (sqrt(n)+sqrt(n+1))^r$$

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SVP
Joined: 07 Nov 2007
Posts: 1738
Location: New York
Re: walker type of problem (round 2) [#permalink]

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05 Aug 2008, 13:24
maratikus wrote:
For any non-negative n and any real r solve equation:

$$sqrt(m) + sqrt(m+1) = (sqrt(n)+sqrt(n+1))^r$$

you want value of m??? interms of n and r.??
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CEO
Joined: 17 Nov 2007
Posts: 3486
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Re: walker type of problem (round 2) [#permalink]

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05 Aug 2008, 14:17
1
It is interesting one. I can solve it but in not good-looking way...
+1
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Intern
Joined: 04 Jun 2008
Posts: 15
Concentration: Marketing, Strategy
GMAT 1: 690 Q48 V35
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WE: Engineering (Non-Profit and Government)
Re: walker type of problem (round 2) [#permalink]

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05 Aug 2008, 14:34
m = [{(4n-1)^r}+1]/4 ??
Director
Joined: 01 Jan 2008
Posts: 601
Re: walker type of problem (round 2) [#permalink]

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06 Aug 2008, 08:15
walker wrote:
It is interesting one. I can solve it but in not good-looking way...
+1

hint: take inverse of both sides and then multiply numerator and denominator of the left side by the same expression.

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: walker type of problem (round 2)   [#permalink] 06 Aug 2008, 08:15
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# walker type of problem (round 2)

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