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# Water is pumped into a 36-gallon pool at pipe R and out of the pool at

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Math Expert
Joined: 02 Sep 2009
Posts: 58323
Water is pumped into a 36-gallon pool at pipe R and out of the pool at  [#permalink]

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07 Mar 2019, 02:50
1
2
00:00

Difficulty:

15% (low)

Question Stats:

86% (02:10) correct 14% (02:59) wrong based on 50 sessions

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Water is pumped into a 36-gallon pool at pipe R and out of the pool at pipe S. If the rate of pumping through R is 3 gallons per hour, how many gallons per hour must be pumped out at pipe S so that the pool is full in exactly 48 hours?

A. 2/9
B. 2/3
C. 3/2
D. 9/4
E. 9/2

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Re: Water is pumped into a 36-gallon pool at pipe R and out of the pool at  [#permalink]

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07 Mar 2019, 06:44
1
Bunuel wrote:
Water is pumped into a 36-gallon pool at pipe R and out of the pool at pipe S. If the rate of pumping through R is 3 gallons per hour, how many gallons per hour must be pumped out at pipe S so that the pool is full in exactly 48 hours?

A. 2/9
B. 2/3
C. 3/2
D. 9/4
E. 9/2

rate will be = pipe R = 3 gph
and rate of pipe S= x gph
so total rate = (3-x) gph
total size of pool = 36
so
36 = (3-x) * 48
x = 2/25 ~ 9/4
IMO D
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Re: Water is pumped into a 36-gallon pool at pipe R and out of the pool at  [#permalink]

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10 Mar 2019, 19:49
1
Bunuel wrote:
Water is pumped into a 36-gallon pool at pipe R and out of the pool at pipe S. If the rate of pumping through R is 3 gallons per hour, how many gallons per hour must be pumped out at pipe S so that the pool is full in exactly 48 hours?

A. 2/9
B. 2/3
C. 3/2
D. 9/4
E. 9/2

Letting s = the number of gallons of water per hour pumped out by pipe S, we can create the equation:

3(48) - s(48) = 36

(3 - s)(48) = 36

3 - s = 36/48

3 - s = 3/4

s = 3 - 3/4 = 9/4

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Re: Water is pumped into a 36-gallon pool at pipe R and out of the pool at   [#permalink] 10 Mar 2019, 19:49
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