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# Find the range of values of x that satisfy the inequality (x + 1)(x –

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Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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Updated on: 23 Dec 2018, 03:41
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Question Stats:

61% (01:37) correct 39% (01:31) wrong based on 135 sessions

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Wavy Line Method Application - Exercise Question #1

Find the range of values of x that satisfy the inequality $$(x + 1)(x – 2) > 4$$

A. x > -2
B. x < -2
C. x > 3
D. x < 3
E. x > 3 or x < -2

Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html

Detailed solution will be posted soon.

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Originally posted by EgmatQuantExpert on 26 Aug 2016, 02:27.
Last edited by Bunuel on 23 Dec 2018, 03:41, edited 4 times in total.
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Re: Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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26 Aug 2016, 09:50
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1

Find the range of values of x that satisfy the inequality $$(x + 1) (x – 2) > 4$$

Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html

Detailed solution will be posted soon.

Please post the options also.

This is what I have calculated.

(x+1)(x-2) > 4

or x^2 -x -2 > 4

or x^2 -x -6 > 0

or (x+2)(x-3)>0

or while drawing on the number line, will get the range of x as (-infinity, -2) U ( 3,infinity)

Please correct me if I missed anything.
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Re: Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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17 Nov 2016, 07:12
(x+1)(x-2)>4
(x-3)(x+2)>0 rearrange the inequality
So zero points are 3 & -2
and -2< x>3 to hold the equation true
I hope my answer is logic
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Re: Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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17 Nov 2016, 08:34
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1

Find the range of values of x that satisfy the inequality $$(x + 1) (x – 2) > 4$$

Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html

Detailed solution will be posted soon.

$$(x + 1) (x – 2) > 4$$ Only when x > 4

So, There can be infinite numbers which are > 4..

Hence I am also with the answer as infinite..
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Re: Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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Updated on: 07 Aug 2018, 21:29
1
Hey Everyone,

Please find below the solution of the given problem :

Solution:

Rewriting the inequality to easily identify the zero points
$$(x + 1) (x – 2) > 4$$

$$x^2 – x – 2 – 4 > 0$$

$$x^2 – x – 6 > 0$$

$$(x – 3) (x+2) > 0$$

Plotting the zero points and drawing the wavy line:

Required Range: x > 3 or x < -2

Correct Answer: Option E

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Originally posted by EgmatQuantExpert on 18 Nov 2016, 02:24.
Last edited by EgmatQuantExpert on 07 Aug 2018, 21:29, edited 2 times in total.
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Re: Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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05 Aug 2018, 02:31
Abhishek009 wrote:
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1

Find the range of values of x that satisfy the inequality $$(x + 1) (x – 2) > 4$$

Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html

Detailed solution will be posted soon.

$$(x + 1) (x – 2) > 4$$ Only when x > 4

So, There can be infinite numbers which are > 4..

Hence I am also with the answer as infinite..

First of all, ONLY x>4 is not correct, even if you input x=3.1 which is slightly greater than 3, the inequality yields value more than 4.
Secondly, for values lesser than -2 also, inequality yields value greater than 4. example: Put x= -3 (which is lesser than -2), inequality gives value more than 4.
However, it is recommended to put the inequality in standard format like <0, >0, <= 0 [(x+1)(x-2)-4>0 ]etc. In such case solving the inequality will be easier..
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Re: Find the range of values of x that satisfy the inequality (x + 1)(x –  [#permalink]

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05 Aug 2018, 02:33
hatemnag wrote:
(x+1)(x-2)>4
(x-3)(x+2)>0 rearrange the inequality
So zero points are 3 & -2
and -2< x>3 to hold the equation true
I hope my answer is logic

x should be lesser than -2 which is -2>x. In your equation it's written opposite.
Re: Find the range of values of x that satisfy the inequality (x + 1)(x –   [#permalink] 05 Aug 2018, 02:33
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