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Wavy Line Method Application - Exercise Question #1

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Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post Updated on: 07 Aug 2018, 21:28
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Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.

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Originally posted by EgmatQuantExpert on 26 Aug 2016, 02:27.
Last edited by EgmatQuantExpert on 07 Aug 2018, 21:28, edited 3 times in total.
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 26 Aug 2016, 09:50
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.


Please post the options also.

This is what I have calculated.

(x+1)(x-2) > 4

or x^2 -x -2 > 4

or x^2 -x -6 > 0

or (x+2)(x-3)>0

or while drawing on the number line, will get the range of x as (-infinity, -2) U ( 3,infinity)

Please correct me if I missed anything.
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 17 Nov 2016, 07:12
(x+1)(x-2)>4
(x-3)(x+2)>0 rearrange the inequality
So zero points are 3 & -2
and -2< x>3 to hold the equation true
I hope my answer is logic
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 17 Nov 2016, 08:34
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.



\((x + 1) (x – 2) > 4\) Only when x > 4

So, There can be infinite numbers which are > 4..

Hence I am also with the answer as infinite..
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Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post Updated on: 07 Aug 2018, 21:29
Hey Everyone,

Please find below the solution of the given problem :

Solution:

Rewriting the inequality to easily identify the zero points
\((x + 1) (x – 2) > 4\)

\(x^2 – x – 2 – 4 > 0\)

\(x^2 – x – 6 > 0\)

\((x – 3) (x+2) > 0\)

Plotting the zero points and drawing the wavy line:

Image

Required Range: x > 3 or x < -2

Correct Answer: Option E

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Originally posted by EgmatQuantExpert on 18 Nov 2016, 02:24.
Last edited by EgmatQuantExpert on 07 Aug 2018, 21:29, edited 2 times in total.
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 05 Aug 2018, 02:31
Abhishek009 wrote:
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.



\((x + 1) (x – 2) > 4\) Only when x > 4

So, There can be infinite numbers which are > 4..

Hence I am also with the answer as infinite..


First of all, ONLY x>4 is not correct, even if you input x=3.1 which is slightly greater than 3, the inequality yields value more than 4.
Secondly, for values lesser than -2 also, inequality yields value greater than 4. example: Put x= -3 (which is lesser than -2), inequality gives value more than 4.
However, it is recommended to put the inequality in standard format like <0, >0, <= 0 [(x+1)(x-2)-4>0 ]etc. In such case solving the inequality will be easier..
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 05 Aug 2018, 02:33
hatemnag wrote:
(x+1)(x-2)>4
(x-3)(x+2)>0 rearrange the inequality
So zero points are 3 & -2
and -2< x>3 to hold the equation true
I hope my answer is logic

x should be lesser than -2 which is -2>x. In your equation it's written opposite.
Re: Wavy Line Method Application - Exercise Question #1 &nbs [#permalink] 05 Aug 2018, 02:33
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