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Wavy Line Method Application - Exercise Question #1

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Wavy Line Method Application - Exercise Question #1  [#permalink]

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Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.

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Originally posted by EgmatQuantExpert on 26 Aug 2016, 01:27.
Last edited by EgmatQuantExpert on 07 Aug 2018, 20:28, edited 3 times in total.
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 26 Aug 2016, 08:50
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.


Please post the options also.

This is what I have calculated.

(x+1)(x-2) > 4

or x^2 -x -2 > 4

or x^2 -x -6 > 0

or (x+2)(x-3)>0

or while drawing on the number line, will get the range of x as (-infinity, -2) U ( 3,infinity)

Please correct me if I missed anything.
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 17 Nov 2016, 06:12
(x+1)(x-2)>4
(x-3)(x+2)>0 rearrange the inequality
So zero points are 3 & -2
and -2< x>3 to hold the equation true
I hope my answer is logic
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 17 Nov 2016, 07:34
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.



\((x + 1) (x – 2) > 4\) Only when x > 4

So, There can be infinite numbers which are > 4..

Hence I am also with the answer as infinite..
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Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post Updated on: 07 Aug 2018, 20:29
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Hey Everyone,

Please find below the solution of the given problem :

Solution:

Rewriting the inequality to easily identify the zero points
\((x + 1) (x – 2) > 4\)

\(x^2 – x – 2 – 4 > 0\)

\(x^2 – x – 6 > 0\)

\((x – 3) (x+2) > 0\)

Plotting the zero points and drawing the wavy line:

Image

Required Range: x > 3 or x < -2

Correct Answer: Option E

Image

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Advanced Topics- Permutation and Combination 1 | Permutation and Combination 2 | Permutation and Combination 3 | Probability
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Originally posted by EgmatQuantExpert on 18 Nov 2016, 01:24.
Last edited by EgmatQuantExpert on 07 Aug 2018, 20:29, edited 2 times in total.
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 05 Aug 2018, 01:31
Abhishek009 wrote:
EgmatQuantExpert wrote:
Wavy Line Method Application - Exercise Question #1


Find the range of values of x that satisfy the inequality \((x + 1) (x – 2) > 4\)




Wavy Line Method Application has been explained in detail in the following post: : http://gmatclub.com/forum/wavy-line-method-application-complex-algebraic-inequalities-224319.html


Detailed solution will be posted soon.



\((x + 1) (x – 2) > 4\) Only when x > 4

So, There can be infinite numbers which are > 4..

Hence I am also with the answer as infinite..


First of all, ONLY x>4 is not correct, even if you input x=3.1 which is slightly greater than 3, the inequality yields value more than 4.
Secondly, for values lesser than -2 also, inequality yields value greater than 4. example: Put x= -3 (which is lesser than -2), inequality gives value more than 4.
However, it is recommended to put the inequality in standard format like <0, >0, <= 0 [(x+1)(x-2)-4>0 ]etc. In such case solving the inequality will be easier..
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Re: Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 05 Aug 2018, 01:33
hatemnag wrote:
(x+1)(x-2)>4
(x-3)(x+2)>0 rearrange the inequality
So zero points are 3 & -2
and -2< x>3 to hold the equation true
I hope my answer is logic

x should be lesser than -2 which is -2>x. In your equation it's written opposite.
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Wavy Line Method Application - Exercise Question #1  [#permalink]

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New post 13 Sep 2018, 10:46
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EgmatQuantExpert wrote:
Hey Everyone,

Please find below the solution of the given problem :

Solution:

Rewriting the inequality to easily identify the zero points
\((x + 1) (x – 2) > 4\)

\(x^2 – x – 2 – 4 > 0\)

\(x^2 – x – 6 > 0\)

\((x – 3) (x+2) > 0\)

Plotting the zero points and drawing the wavy line:

Image

Required Range: x > 3 or x < -2

Correct Answer: Option E

Image


Hi EgmatQuantExpert,

Well there are no answer choices that we can mark . Since you have marked the correct answer choice as "E", looks like you have missed to add the choices in the original post.

Good if you could edit and post the answer choices.

HiBunuel,

Request if you could notify the user to post the answer choices for the questions. Also it breaks the rules of posting questions . Rule No 8.

There are several posts by the user in which they have missed the answer choices.

https://gmatclub.com/forum/wavy-line-me ... 24323.html
https://gmatclub.com/forum/wavy-line-me ... 24324.html

Many users have repeatedly requested for answer choices. So in the best interest of the forum i am here writing and requesting again for the same.

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Wavy Line Method Application - Exercise Question #1 &nbs [#permalink] 13 Sep 2018, 10:46
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