Nups1324
ScottTargetTestPrep
hoaivinh
What are the coordinates for the point on Line AB (see figure) that is three times as far from A as from B, and that is in between points A and B?
Attachment:
mgmat.png
OA:
Solution:
First we can find M, the midpoint of A and B:
M = ((-5 + (-2))/2, (6 + 0)/2) = (-7/2, 3)
Next, we find N, the midpoint of M and B:
N = (-7/2 + (-2))/2, (3 + 0)/2) = (-11/4, 3/2)
Notice that now N is three times as far from A as from B.
Answer: (-11/4, 3/2) Hi
ScottTargetTestPrep,
First you figured out M (Midpoint) which has to be equidistant from A and B. Then you figured out N (Midpoint of M and B). Then how is N three times as far from A as from B.
Three times as far from A as from B means it has to be 3 times as far from both A as well as B right?
It'll be great if you'd help me understand
Thank you
Posted from my mobile deviceThree times as far from A as from B means the distance between the point and A is equal to three times the distance between the point and B. So, if the distance between N and B is d, then the distance between N and A should be 3d so that we can say the point N is three times as far from A as from B.
To elaborate further, M is the midpoint of A and B, so the distance between A and M is equal to the distance between M and B. Let's call this distance s. N is the midpoint between M and B, so the distance between M and N is equal to the distance between N and B. Since we already represented the distance between M and B by s, the distance between M and N is s/2 and the distance between N and B is also s/2.
Notice that the distance between A and N is the sum of the distance between A and M and the distance between M and N. The former is s and the latter is s/2, so the distance between A and N is s + s/2 = 3s/2, which is precisely three times the distance between N and B, which is s/2.