|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
29 Aug 2018, 01:52
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:38) correct
10%
(02:14)
wrong
based on 109
sessions
History
Date
Time
Result
Not Attempted Yet
What is area of the sector ACBO in the circle above with center O, if the radius of the circle is 6 and the length of the arc ACB is 2π?
A. \(6\pi\)
B. \(6\pi - 6\)
C. \(6\pi - 9\)
D. \(6\pi-\frac{25}{2}\)
E. \(6\pi-9\sqrt{3}\)
Attachment:
circle7168.jpg [ 26.19 KiB | Viewed 4499 times ]
29 Aug 2018, 06:39
Kudos
Bookmarks
Bunuel
Circumference = 2π(radius)
Given: radius is 6
So, circumference = 2π(6) = 12π
We're told the arc ACB has length 2π
2π/12π = 1/6.
So, the arc represents 1/6 of the circle's entire circumference
This also means sector ACBO represents 1/6 of the circle's area
Area of circle = π(radius)²
So, area of this circle = π(6)² = 36π
So, the area of sector ACBO = 1/6 of 36π
= 6π
Answer: A
Cheers,
Brent
General Discussion
29 Aug 2018, 01:58
Kudos
Bookmarks
Bunuel
Length of the arc = \(2 pi r @/360\) =\(2 pi\)
@=60
area of sector = \(pi r^2 @/360\) = \(pi * 36/6\) = 6 pi
