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1) X^X=|X|
What about x=0?
0^0=|0|
so the statement should be true for x=0 and 1. Am I wrong?
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Eden
What is integer X?
(1) X^X=|X|
(2) X^2=|X^3|

Answer is but I'm not so sure..

Eden
1) X^X=|X|
What about x=0?
0^0=|0|
so the statement should be true for x=0 and 1. Am I wrong?

0^0, in some sources equals to 1, some mathematicians say it's undefined. Note that the case of 0^0 is not tested on the GMAT. (But anyway \(0^0\neq{0}\))

Given: \(x=integer\). Q: \(x=?\)

(1) \(x^x=|x|\) --> \(x=1\). Sufficient.
(2) \(x^2=|x^3|\) --> \(x=1\) or \(x=-1\) or \(x=0\). Not sufficient.

Answer: A.

Hope it helps.
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sid4674
What is integer X?
(1) X^X=|X|
(2) X^2=|X^3|

For 1) x^x=|x|

X =1, 1*1=|1|=>1=1
X=-1, -1*-1=|-1|=>1=1

hence A is not sufficient, could anyone please explain how statement one alone is sufficient.

Your calculation is not correct.

Statement (1) is: \(x^x=|x|\), so if \(x=-1\), then \((-1)^{-1}=\frac{1}{(-1)^1}=\frac{1}{-1}=-1\neq|-1|=1\).
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Is it valid if for statement 2 we divide both sides by x^2, hence obtaining

x = abs (x)

Therefore any >=0 number will do

Thanks
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J
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