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19 Dec 2018, 01:23
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:45) correct
16%
(02:28)
wrong
based on 327
sessions
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What is the area of a triangle with vertices (–2, 4), (2, 4) and (–6, 6) in the coordinate plane?
A. 2
B. 3
C. 4
D. 5
E. 6
A. 2
B. 3
C. 4
D. 5
E. 6
08 Jan 2019, 10:40
Kudos
Bookmarks
Bunuel
When we sketch the points . . .
. . . we see that the triangle's base has length 4, and the triangle's height is 2
Area of triangle = (base)(height)/2
= (4)(2)/2
= 4
Answer: C
RELATED VIDEO FROM OUR COURSE
General Discussion
19 Dec 2018, 22:03
Kudos
Bookmarks
Bunuel
Area of a triangle with its vertices \((x_1,y_1), (x_2,y_2),\) and \((x_3,y_3)\):-
A = \(\frac{{|x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})|}}{2}\)
Or, A=\(\frac{{|-2(4-6)+2(6-4)+6(4-4)|}}{2}\)
Or, A=\(\frac{{|-2(-2)+2(2)+6(0)|}}{2}\)
Or, A=4
Ans. (C)
