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What is the area of the figure above?

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Joined: 02 Sep 2009
Posts: 53063
What is the area of the figure above?  [#permalink]

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New post 17 Jan 2019, 22:35
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

73% (00:50) correct 27% (01:10) wrong based on 28 sessions

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G
Joined: 18 Aug 2017
Posts: 1894
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
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Re: What is the area of the figure above?  [#permalink]

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New post 18 Jan 2019, 03:46
Bunuel wrote:
Image
What is the area of the figure above?

A 18
B 24
C 26
D 32
E 40

Attachment:
2019-01-18_1033.png


draw a line we get a triangle in 3:4:5
so width of rectangle = 4
area = 0.5 * 4*3 +5*4 = 26
IMO C
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Re: What is the area of the figure above?  [#permalink]

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New post 19 Jan 2019, 00:58
Area of a trapezoid is 0.5(height)(a+b) where a+b is the top and bottom of the trapezoid

The height in the figure is found using the pythagorean triple 3-4-5.
The base is 3 (8-5), hypotenuse 5, so height must be 4.

0.5(4)(5+8)=2·13=26
C
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Re: What is the area of the figure above?  [#permalink]

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New post 19 Jan 2019, 01:46
Easy one ,Drop a line from <ABC to be perpendicular to line DC let’s name it E now since line DC is 8 then line EC is 3
Now we can recognize a Pythagorean triplet 3:4:5 or better still solve for line BE with pythagoras theory
Since the figure is a trapezoid as line AB || DC but different in length
We average line AB and DC and multiply by BE which becomes the height
Therefore 1/2(5+8)x 4=26
Answer is C

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Re: What is the area of the figure above?   [#permalink] 19 Jan 2019, 01:46
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What is the area of the figure above?

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