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What is the area of the rectangular region above?

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What is the area of the rectangular region above?  [#permalink]

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New post Updated on: 30 Jan 2018, 21:00
2
6
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A
B
C
D
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What is the area of the rectangular region above?

(1) l + w = 6.
(2) d^2 = 20

Attachment:
untitled.PNG
untitled.PNG [ 1.94 KiB | Viewed 7752 times ]

Originally posted by heygirl on 24 Feb 2011, 11:39.
Last edited by Bunuel on 30 Jan 2018, 21:00, edited 2 times in total.
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 24 Feb 2011, 11:46
5
1
(1)
\(l+w = 6\)
\((l+w)^2 = l^2+w^2+2w*l=36\)
\(w*l=\frac{36-l^2-w^2}{2}\)
Not Sufficient.

(2)
\(d^2=l^2+w^2=20\)
Not Sufficient.

Combining both;
\(w*l=\frac{36-(l^2+w^2)}{2}\)
\(w*l=\frac{36-20}{2}\)
\(w*l=\frac{16}{2}\)
\(w*l=8\)(Area is w*l)

Sufficient.

Ans: "C"
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 24 Feb 2011, 11:49
Thanks!
Actually, can we not use the pythagorean theorem and 45-45-90 triangle rule to get l and w using (2)?
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What is the area of the rectangular region above?  [#permalink]

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New post 24 Feb 2011, 12:10
2
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What is the area of the rectangular region above?

\(area=lw=?\)

(1) l + w = 6. Not sufficient to get the value of \(lw\).
(2) d^2 = 20 --> \(l^2 +w^2 = 20\). Not sufficient to get the value of \(lw\).

(1)+(2) Square (1): \(l^2+2lw+w^2=36\), as from (2) \(l^2 +w^2 = 20\) then \(2lw+20=36\) --> \(lw=8\). Sufficient.

Answer: C.

heygirl wrote:
Thanks!
Actually, can we not use the pythagorean theorem and 45-45-90 triangle rule to get l and w using (2)?


Usually the diagonal does not divide a rectangle into two 45-45-90 triangles (it'll be correct only for squares, so when l=w).

Similar questions:
http://gmatclub.com/forum/need-some-hel ... 05414.html
http://gmatclub.com/forum/og12-d48-102246.html
http://gmatclub.com/forum/one-more-geometry-96381.html
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 24 Feb 2011, 12:12
1
Thanks for letting me know Bunuel. I shall follow the rules henceforth!!
I actually thought b could be the right answer here. I made a wrong assumption :o : diag of a rect make 45 degrees!
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 09 Mar 2011, 00:19
Lolaergasheva wrote:
What is the area of the rectangular region ?
(1) l + w = 6
(2) d^2 = 20


Area of rectangular region is given by \(l*w\).

Statement 1 gives us,\(l+w=6\), but l and w can take any values, so insufficient

Statement 2 gives us \(d^2 = 20\) . Assuming that d refers to length of diagonal, we have \(d^2 = l^2 + w^2 = 20\). Again l and w can take multiple values, so insufficient.

Combining 1 and 2,

we get \(l+w=6\) ... (1)

and \(l^2 + w^2 = 20\).... (2)

Squaring both sides of (1), we get

so, \(l^2 + w^2 + 2l*w = 36\)

Putting \(l^2 + w^2 = 20\) in above we get \(2l*w = 16\) or \(l*w = 8\)

So, sufficient. Answer C
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 07 Sep 2015, 07:28
1
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and equations ensures a solution.


What is the area of the rectangular region above?

(1) l + w = 6. Not sufficient to get the value of .
(2) d^2 = 20

In the original condition we have 2 variables for the rectangle(width, length) and thus we need 2 variables to match the number of variables and equations. Since there is 1 each in 1) and 2), C is likely the answer.
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 30 Jan 2018, 19:03
Bunuel wrote:
heygirl wrote:
What is the area of a rectangle with length l and width w?
(1)l+w=6
(2)d^2=20(d is the diagonal)


heygirl, please read and follow: http://gmatclub.com/forum/how-to-improv ... 99451.html

So please:
Make sure you type the question in exactly as it was stated from the source. Yuo should not reword or/and shorten the questions.

Original question:

Attachment:
untitled.PNG
What is the area of the rectangular region above?

\(area=lw=?\)

(1) l + w = 6. Not sufficient to get the value of \(lw\).
(2) d^2 = 20 --> \(l^2 +w^2 = 20\). Not sufficient to get the value of \(lw\).

(1)+(2) Square (1): \(l^2+2lw+w^2=36\), as from (2) \(l^2 +w^2 = 20\) then \(2lw+20=36\) --> \(lw=8\). Sufficient.

Answer: C.

heygirl wrote:
Thanks!
Actually, can we not use the pythagorean theorem and 45-45-90 triangle rule to get l and w using (2)?


Usually the diagonal does not divide a rectangle into two 45-45-90 triangles (it'll be correct only for squares, so when l=w).

Similar questions:
http://gmatclub.com/forum/need-some-hel ... 05414.html
http://gmatclub.com/forum/og12-d48-102246.html
http://gmatclub.com/forum/one-more-geometry-96381.html


Bunuel, I screwed up and assumed I was to use the 30:60:90 triangle rule for statement #2 (since it's a rectangle).

How am I supposed to know that rule won't work for this question? Is it because d^2 = 20 -> d= 4 square root 5, but not 4 square root 3?
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 30 Jan 2018, 21:07
OCDianaOC wrote:
Bunuel wrote:
heygirl wrote:
What is the area of a rectangle with length l and width w?
(1)l+w=6
(2)d^2=20(d is the diagonal)


heygirl, please read and follow: http://gmatclub.com/forum/how-to-improv ... 99451.html

So please:
Make sure you type the question in exactly as it was stated from the source. Yuo should not reword or/and shorten the questions.

Original question:

Attachment:
untitled.PNG
What is the area of the rectangular region above?

\(area=lw=?\)

(1) l + w = 6. Not sufficient to get the value of \(lw\).
(2) d^2 = 20 --> \(l^2 +w^2 = 20\). Not sufficient to get the value of \(lw\).

(1)+(2) Square (1): \(l^2+2lw+w^2=36\), as from (2) \(l^2 +w^2 = 20\) then \(2lw+20=36\) --> \(lw=8\). Sufficient.

Answer: C.

heygirl wrote:
Thanks!
Actually, can we not use the pythagorean theorem and 45-45-90 triangle rule to get l and w using (2)?


Usually the diagonal does not divide a rectangle into two 45-45-90 triangles (it'll be correct only for squares, so when l=w).

Similar questions:
http://gmatclub.com/forum/need-some-hel ... 05414.html
http://gmatclub.com/forum/og12-d48-102246.html
http://gmatclub.com/forum/one-more-geometry-96381.html


Bunuel, I screwed up and assumed I was to use the 30:60:90 triangle rule for statement #2 (since it's a rectangle).

How am I supposed to know that rule won't work for this question? Is it because d^2 = 20 -> d= 4 square root 5, but not 4 square root 3?


Knowing only the length of a diagonal of a rectangle does not allow to find its adjacent angles. You can squeeze or stretch a rectangle with any length of a diagonal along one of its sides to get any adjacent lengths from 0 to 90 not inclusive.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: What is the area of the rectangular region above?  [#permalink]

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New post 22 Apr 2018, 04:38
Bunuel wrote:
Image
What is the area of the rectangular region above?

\(area=lw=?\)

(1) l + w = 6. Not sufficient to get the value of \(lw\).
(2) d^2 = 20 --> \(l^2 +w^2 = 20\). Not sufficient to get the value of \(lw\).

(1)+(2) Square (1): \(l^2+2lw+w^2=36\), as from (2) \(l^2 +w^2 = 20\) then \(2lw+20=36\) --> \(lw=8\). Sufficient.

Answer: C.

heygirl wrote:
Thanks!
Actually, can we not use the pythagorean theorem and 45-45-90 triangle rule to get l and w using (2)?



Usually the diagonal does not divide a rectangle into two 45-45-90 triangles (it'll be correct only for squares, so when l=w).

Similar questions:
http://gmatclub.com/forum/need-some-hel ... 05414.html
http://gmatclub.com/forum/og12-d48-102246.html
http://gmatclub.com/forum/one-more-geometry-96381.html



Bunuel why are you squaring statement one l + w = 6 ?? :? the formula for area of rectangle is L*W , isnt it :?
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 22 Apr 2018, 11:17
1
dave13 wrote:
Bunuel wrote:
Image
What is the area of the rectangular region above?

\(area=lw=?\)

(1) l + w = 6. Not sufficient to get the value of \(lw\).
(2) d^2 = 20 --> \(l^2 +w^2 = 20\). Not sufficient to get the value of \(lw\).

(1)+(2) Square (1): \(l^2+2lw+w^2=36\), as from (2) \(l^2 +w^2 = 20\) then \(2lw+20=36\) --> \(lw=8\). Sufficient.

Answer: C.

heygirl wrote:
Thanks!
Actually, can we not use the pythagorean theorem and 45-45-90 triangle rule to get l and w using (2)?



Usually the diagonal does not divide a rectangle into two 45-45-90 triangles (it'll be correct only for squares, so when l=w).

Similar questions:
http://gmatclub.com/forum/need-some-hel ... 05414.html
http://gmatclub.com/forum/og12-d48-102246.html
http://gmatclub.com/forum/one-more-geometry-96381.html



Bunuel why are you squaring statement one l + w = 6 ?? :? the formula for area of rectangle is L*W , isnt it :?


Hello Dave

I think Bunuel is doing this because he sees two equations from two statements: one equation says that l + w = 6 and the other says that l^2 + w^2 = 20. But he has to find l*w. So how to find l*w from l+w and l^2 + w^2. Immediately the formula which comes to mind is:
(l+w)^2 = l^2 + w^2 + 2*l*w.
We can substitute the values of l+w and l^2 + w^2 in the above formula and we can get the value of l*w. Hope this is clear.
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 24 Apr 2018, 01:44
4
Need to find area = l*w
1. l+w=6 --> sqrn both sides --> l^2 + w^2 + 2wl=36 -eqn(a)
INSUFFICIENT
2. d^2=20 --> l^2+w^2=d^2=20 -eqn(b)
INSUFFICIENT

Consider eqn (a) and (b)
20 +2wl=36 --> Solve for wl

Ans -> C
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 08 May 2018, 07:59
Area=LW
We got L*L + W*W=D*D
Converted to

=(L+W)^2 -2LW=20

=36-20=2LW

2LW=16

LW =8

Both statements are required
C is answer

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Re: What is the area of the rectangular region above?  [#permalink]

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New post 26 Jul 2018, 17:49
Bunuel

When you square statement 1 why do you are you doing this: (l+w)^2 and not l^2+w^2. When squaring, I've never done it like this.
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Re: What is the area of the rectangular region above?  [#permalink]

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New post 26 Jul 2018, 20:20
Re: What is the area of the rectangular region above? &nbs [#permalink] 26 Jul 2018, 20:20
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