It is currently 21 Nov 2017, 05:30

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is the average (arithmetic mean) of eleven consecutive

Author Message
Senior Manager
Joined: 02 Sep 2006
Posts: 253

Kudos [?]: 75 [0], given: 0

What is the average (arithmetic mean) of eleven consecutive [#permalink]

### Show Tags

05 Apr 2007, 00:36
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (00:16) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the average (arithmetic mean) of eleven consecutive integers?

1. The average of the first 9 integers is 7.

2. The average of the last 9 intergers is 9.

Kudos [?]: 75 [0], given: 0

Senior Manager
Joined: 20 Feb 2007
Posts: 256

Kudos [?]: 63 [0], given: 0

### Show Tags

05 Apr 2007, 00:54
I think the answer should be D.

What is the OA?

Kudos [?]: 63 [0], given: 0

Director
Joined: 13 Nov 2003
Posts: 788

Kudos [?]: 64 [0], given: 0

Location: BULGARIA

### Show Tags

05 Apr 2007, 01:22
Hi,
Think that D is not correct.
The consecutive integers may be in increasing or decreasing order which will give different results.
Think it is E

Kudos [?]: 64 [0], given: 0

Director
Joined: 18 Jul 2006
Posts: 523

Kudos [?]: 71 [0], given: 0

### Show Tags

05 Apr 2007, 01:24
Agree D.

integers may be x, x+1, ... x+10 then
A => 9x+36=63 => x=3 => suff
B => 9x+54=81 => x=3 => suff

Kudos [?]: 71 [0], given: 0

Manager
Joined: 15 Nov 2006
Posts: 216

Kudos [?]: 80 [0], given: 0

Location: Ohio

### Show Tags

05 Apr 2007, 18:37
Juaz,

How did you get A => 9x+36=63 and 9x+54=81

Kudos [?]: 80 [0], given: 0

Intern
Joined: 04 May 2004
Posts: 47

Kudos [?]: 34 [0], given: 0

Location: India

### Show Tags

05 Apr 2007, 21:44
nitinneha wrote:
Juaz,

How did you get A => 9x+36=63 and 9x+54=81

A is first nine integars
x, x+1, ... , x+8 = 9x + (1+2+...+8) = 9x + 36

And in my opinion, we should not worry about calculating the answer. We should concentrate on finding if we can calculate it or not.

Two equations and two variables will give answer. I will leave the question the moment i have the equations.

Kudos [?]: 34 [0], given: 0

Manager
Joined: 29 Nov 2006
Posts: 56

Kudos [?]: [0], given: 0

### Show Tags

06 Apr 2007, 02:20
nitinneha wrote:
Juaz,

How did you get A => 9x+36=63 and 9x+54=81

x + (x+1) + (x+2) + ...(x+8) = 9x+ (1+2+3+...+8) = 9x + (8)(9)/2 (sum of consecutive intergers)= 9x+36

hope this clears it up for u

Kudos [?]: [0], given: 0

06 Apr 2007, 02:20
Display posts from previous: Sort by