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What is the greatest value of the positive integer p such that 2^p is

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What is the greatest value of the positive integer p such that 2^p is  [#permalink]

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New post 01 Apr 2018, 10:36
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  25% (medium)

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67% (00:44) correct 33% (01:08) wrong based on 57 sessions

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Re: What is the greatest value of the positive integer p such that 2^p is  [#permalink]

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New post 01 Apr 2018, 10:43
Bunuel wrote:
What is the greatest value of the positive integer p such that 2^p is a factor of 80^50?

(A) 4
(B) 10
(C) 50
(D) 100
(E) 200


80^50=(2^200*5^50)

so greatest value is 200

option E
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What is the greatest value of the positive integer p such that 2^p is  [#permalink]

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New post Updated on: 07 Apr 2018, 15:20
Bunuel wrote:
What is the greatest value of the positive integer p such that 2^p is a factor of 80^50?

(A) 4
(B) 10
(C) 50
(D) 100
(E) 200


we are asked to find the greatest value of the positive integer p. In order to find out the greatest value of p as a exponent of base 2 we have to factorize 80^50.

(2*2*2*2*5)^50
={(2^4)*5}^50
=(2^200 )*5^50

so, 2^200 shows that the greatest value of p. The correct answer is E.

Originally posted by selim on 06 Apr 2018, 13:39.
Last edited by selim on 07 Apr 2018, 15:20, edited 1 time in total.
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What is the greatest value of the positive integer p such that 2^p is  [#permalink]

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New post 07 Apr 2018, 12:15
Bunuel wrote:
What is the greatest value of the positive integer p such that 2^p is a factor of 80^50?

(A) 4
(B) 10
(C) 50
(D) 100
(E) 200

\((ab)^{n} = a^{n}b^{n}\)
\((a^{m})^{n}=a^{(m*n)}\)

Find prime factors of 80, raise to 50th power
\(80 = (2*2*2*2*5) = (2^4*5)\)
\((2^4*5)^{50}=\)
\((2^4)^{50}*5^{50}=\)
\(2^{200}5^{50}\)


5 to any power ends in 5. NEVER divisible by 2. The other factor of \((80)^{50}=2^{200}\)

\((80)^{50}=\)
\((2^{200}*5^{50})=(2^{p}*5^{50})\)
\(2^{p}=2^{200}\)
\(p=200\)

There are 200 powers of 2 in \((80)^{50}\)

Answer E

selim , I think there is a small typo in your answer: \(5^{200}\) :-)
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What is the greatest value of the positive integer p such that 2^p is &nbs [#permalink] 07 Apr 2018, 12:15
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