|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
15 Apr 2019, 01:20
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:33) correct
32%
(01:41)
wrong
based on 190
sessions
History
Date
Time
Result
Not Attempted Yet
[GMAT math practice question]
What is the largest multiple of 24 that can be written using each of the digits 0, 1, 2, … , 9 exactly once?
A. 9876543210
B. 9876543120
C. 987654102
D. 1234567890
E. 1234567980
What is the largest multiple of 24 that can be written using each of the digits 0, 1, 2, … , 9 exactly once?
A. 9876543210
B. 9876543120
C. 987654102
D. 1234567890
E. 1234567980
15 Apr 2019, 01:52
Kudos
Bookmarks
24 is 8*3
First do the divisibilty test of 8 which is check the last 3 digits if its divisible by 8
Only B survives
Then do the divisibilty test of 3. Add all the digits and check if its divisible by 3
Hence B
Posted from my mobile device
First do the divisibilty test of 8 which is check the last 3 digits if its divisible by 8
Only B survives
Then do the divisibilty test of 3. Add all the digits and check if its divisible by 3
Hence B
Posted from my mobile device
17 Apr 2019, 01:23
Kudos
Bookmarks
=>
A number is a multiple of \(24\) precisely when it is a multiple of both \(3\) and \(8\).
The sum of \(0, 1, 2, … , 9, “0 + 1 + 2 + … + 9 = 45”\) is a multiple of \(3\). Thus, a number which uses each of the digits \(0, 1, 2, … , 9\) exactly once is a multiple of \(3\).
In order for a number to be a multiple of \(8\), the last three digits of the number must be a multiple of \(8\). And the smallest multiple of \(8\) that can be formed using three of the digits \(0, 1, 2, … , 9\) is \(120\).
Thus, the biggest possible multiple of \(24\) is \(9876543120\).
Therefore, B is the answer.
Answer: B
A number is a multiple of \(24\) precisely when it is a multiple of both \(3\) and \(8\).
The sum of \(0, 1, 2, … , 9, “0 + 1 + 2 + … + 9 = 45”\) is a multiple of \(3\). Thus, a number which uses each of the digits \(0, 1, 2, … , 9\) exactly once is a multiple of \(3\).
In order for a number to be a multiple of \(8\), the last three digits of the number must be a multiple of \(8\). And the smallest multiple of \(8\) that can be formed using three of the digits \(0, 1, 2, … , 9\) is \(120\).
Thus, the biggest possible multiple of \(24\) is \(9876543120\).
Therefore, B is the answer.
Answer: B
