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30 Jan 2023, 05:01
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
93% (00:49) correct
7%
(01:08)
wrong
based on 29
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure above, what is the length of AD?
A. 2√10
B. 4√10
C. 2√5
D. 4√5
E. √10
Attachment:
GEO.jpg [ 3.59 KiB | Viewed 1852 times ]
30 Jan 2023, 22:10
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Bunuel
Draw a line, DZ, parallel to CB.
\(\angle DZA = 90\)
DZ = CB = 6
AZ = 12 - 10 = 2
\(AD^2 = AZ^2 + DZ^2\)
\(AD = \sqrt{6^2 + 2^2}\)
= \(\sqrt{40}\)
= \(2 \sqrt{10}\)
Option A
Attachments
Screenshot 2023-01-31 103818.jpg [ 6.97 KiB | Viewed 1057 times ]
31 Jan 2023, 08:49
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Bunuel
\(6^2 + (12-10)^2 = 40\) = \(2√10 \){Better to mentally construct some part to solve time} , Answer must be (A)
