It is currently 19 Feb 2018, 16:07

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

What is the maximum number of cubes, each 3 centimeters on an edge, th

Author Message
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 43810
What is the maximum number of cubes, each 3 centimeters on an edge, th [#permalink]

Show Tags

30 Nov 2017, 21:58
00:00

Difficulty:

25% (medium)

Question Stats:

92% (00:29) correct 8% (00:38) wrong based on 24 sessions

HideShow timer Statistics

What is the maximum number of cubes, each 3 centimeters on an edge, that can be packed into a rectangular box with inside dimensions as shown above?

(A) 360
(B) 120
(C) 90
(D) 40
(E) 20

[Reveal] Spoiler:
Attachment:

2017-12-01_0947_002.png [ 5.29 KiB | Viewed 371 times ]
[Reveal] Spoiler: OA

_________________
Senior Manager
Joined: 17 Oct 2016
Posts: 324
Location: India
Concentration: Operations, Strategy
GPA: 3.73
WE: Design (Real Estate)
Re: What is the maximum number of cubes, each 3 centimeters on an edge, th [#permalink]

Show Tags

30 Nov 2017, 22:23
D

Along the side of length 12 only four cubes can be placed. Similarly along the side of 15 only 5 cubes can be placed. Hence 4*5=20 cubes can be placed at bottom.

Also one more layer of cubes can be placed along the side of length 6. Hence 20*2=40 cubes only can be placed in the given arrangement.

Sent from my iPhone using GMAT Club Forum
_________________

Help with kudos if u found the post useful. Thanks

VP
Joined: 22 May 2016
Posts: 1329
What is the maximum number of cubes, each 3 centimeters on an edge, th [#permalink]

Show Tags

02 Dec 2017, 09:34
Bunuel wrote:

What is the maximum number of cubes, each 3 centimeters on an edge, that can be packed into a rectangular box with inside dimensions as shown above?

(A) 360
(B) 120
(C) 90
(D) 40
(E) 20

[Reveal] Spoiler:
Attachment:
2017-12-01_0947_002.png

Box's total volume / each cube's volume = number of cubes

Box's total volume: L* W* H
15 * 12 * 6 = 1,080

Shortcut: Double and halve factors (combine last two: 12*6 = 72)
15 * 72
30 * 36
60 * 18
120 * 9 = 1,080

Each cube's volume: 3 * 3 * 3 = 27

$$\frac{1,080}{27} = 40$$ cubes

OR
Box side 15 = 3 * 5
Box side 12 = 3 * 4
Box side 6 = 3 * 2

Volume of each cube: (3*3*3) = 27

$$\frac{BoxVolume}{OneCubeVolume}=\frac{3*5*3*4*3*2}{3*3*3}=5*4*3=40$$

_________________

At the still point, there the dance is. -- T.S. Eliot
Formerly genxer123

What is the maximum number of cubes, each 3 centimeters on an edge, th   [#permalink] 02 Dec 2017, 09:34
Display posts from previous: Sort by