Mean age = Total Sum of ages of all the students in all the schools / Total number of students

1.) Sum of ages of students in one school / number of students in that school = 12
=> Sum of ages of students in one school = 12 * (number of students in that school )
Similarly,
Sum of ages of students in second school / number of students in that school = 12
=> Sum of ages of students in Second school = 12 * (number of students in that school )

Adding all these,

Sum of ages of all students in all schools = 12 * (total number of students)
=> Mean age = 12
Sufficient
2.) only gives, number of students in each school. in sufficient

ans A

If the average at each school is the same, then the overall average will be equal to the average at each school, so S1 is sufficient and the answer should be A.
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Yeah, the answer is A. Thank you very much for explanations. But I thought this question can not be so easy. While reading choice 1 at first, I remembered that term "average" applies to mean, median and mode. And thus, I picked answer E, because of this uncertainty...going crazy with GMAT

Let there be 2 schools A and B
To find. Mean age = sum of ages of students in A and B / sum of number of students in A and B
= age A + age B/ no. A + no. B

1. The average age of the students in each of the city's schools is 12.
We have two schools A and B.
For A.
Avg1 = sum of ages of student in school A/ no. of student in school A
12 = sum of ages of student in school A/ no. of student in school A

sum of ages of student in school A = 12 * no. of student in school A

Avg2=sum of ages of student in school B/ no. of student in school B
12 = sum of ages of student in school B/ no. of student in school B

sum of ages of student in school B = 12 * no. of student in school B

Mean Age=sum of ages of student in school A+sum of ages of student in school B /no. of student in school A+ no. of student in school B
= 12 * no. of student in school A + 12 * no. of student in school B/no. of student in school A+ no. of student in school B
=12(no. of student in school A + no. of student in school B)/no. of student in school A+ no. of student in school B
=12.

Sufficient.

2. The number of students in each of the city's schools is 70.
Mean Age=sum of ages of student in school A+sum of ages of student in school B /no. of student in school A+ no. of student in school B
= sum of ages of student in school A+sum of ages of student in school B /70+70
=sum of ages of student in school A+sum of ages of student in school B /140.

sum of ages of student in school A+sum of ages of student in school B --we do not know this.

Insufficient.

OA A.
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A


1 is enough as if the average of all the schools are 12 means then mean is also 12

What a question ! :D

if average age of students at each school is 12.. that means..mean of every school will be ..

for example..there are 5 schools...(12,12,12,12,12) there means will be 12..
Ans is A..

statement 2..is insufficient..
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